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Gwar [14]
2 years ago
15

Consider the following system at equilibrium. CaCO3(s) Double headed arrow. Ca2 (aq) CO32â€""(aq) The addition of which compound

will cause a shift in equilibrium because of a common ion effect? CCl4 CO2 CuSO4 Na2CO3.
Chemistry
1 answer:
Dominik [7]2 years ago
6 0

The compound that has been capable to shift the equilibrium with common ion effect has been  \rm \bold{Na_2CO_3}.  Thus, option D is correct.

The complete equation for the decomposition of calcium carbonate has been:

\rm CaCO_3\rightleftharpoons Ca^2^+\;+\;CO_3^2^-

The equilibrium has been the state in the reaction, when the number of products and has been equivalent to the number of reactants. The increase or decrease in the concentration of any of the reactant or product results in the shift in the equilibrium.

For the given reaction, the addition of Calcium or carbonate ions to the solution results in the increase in the product concentration with the common ion effect, and thereby shifts the equilibrium condition.

The ions liberated by the following compounds has been:

\rm CCl_4\;=\text{not dissolved}\\CO_2\;+\;H_2O\leftrightharpoons CO_3^-\;+\;H^+\\CuSO_4\leftrightharpoons Cu^2^+\;+\;SO_4^2^-\\Na_2CO_3\leftrightharpoons 2\;Na^+\;+\;CO_3^-

The compound, that has been capable of liberating the carbonate ions in the medium has been \rm \bold{Na_2CO_3}. Thus, it results in the shift of the equilibrium due to common ion effect. Hence, option D is correct.

For more information about common ion effect, refer to the link:

brainly.com/question/4090548

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Ava Gadro is performing a titration in order to determine the amount of sodium hydroxide, NaOH(aq), in 81 mL of an aqueous solut
Irina-Kira [14]

Answer:

M = 0.050 M

Explanation:

WE have an acid base reaction between NaOH and HCl. The reaction is as follow:

HCl + NaOH -------> NaCl + H₂O

As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:

M₁V₁ = M₂V₂       1: acid;   2: base

This expression is used when the reactions has reached the equivalence point. As we want to know the concentration of the base, we just solve for M₂ above so:

M₂ = M₁V₁ / V₂

All we have to do now is replace the given values and solve for the concentration:

M₂ = 0.15 * 27 / 81

<h2>M₂ = 0.050 M</h2><h2>This is the concentration of the base</h2>
5 0
3 years ago
Which of the followings are true about D-glucose and L-glucose? A. They are furanose B. They are stereoisomers C. They are enant
zaharov [31]

Answer:

B. They are stereoisomers

C. They are enantiomers

Explanation:

Let us consider all the options

A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)

B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.

C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions

D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case

E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid

4 0
3 years ago
(I will give a Brainliest)
gogolik [260]
The particles would be more scattered out as those three factors increase.
3 0
3 years ago
Read 2 more answers
What is the mass of one mole of Ca(OH)2?
marshall27 [118]

Answer:

74.10g/mol

Explanation:

The mass of one mole of Ca(OH)₂ is the molar mass of the compound.

To solve this problem, we add the atomic masses of the species in the compound;

 Atomic mass of Ca = 40.078g/mol

                             O = 15.9994g/mol

                            H = 1.0079g/mol

So;

  Molar mass  =  40.078 + 2(15.9994 +1.0079 )  = 74.10g/mol

3 0
3 years ago
A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 mL of water rising the water level
djyliett [7]

Answer:

The answer is

<h2>2.64 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 611 g

volume = final volume of water - initial volume of water

volume = 256.7 - 25.1 = 231.6 mL

The density of the metal is

density =  \frac{611}{231.6}  \\  = 2.638169257...

We have the final answer as

<h3>2.64 g/mL</h3>

Hope this helps you

5 0
3 years ago
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