All categories

3 years ago

PLEASE HELP!!! What is the mass of one lead atom in amu?

Chemistry

2 answers:

alexandr402 [8]3 years ago

7 0

Answer: 207.2

Explanation:

In imprecise terms, one AMU is the average of the proton rest mass and the neutron rest mass. This is approximately 1.67377 x 10 -27 kilogram (kg), or 1.67377 x 10 -24 gram (g). The mass of an atom in AMU is roughly equal to the sum of the number of protons and neutrons in the nucleus.

scoundrel [369]3 years ago

3 0

Answer:207.2

Percent composition by element

Element Symbol Atomic Mass

Lead Pb 207.2

Explanation: googled it

You might be interested in

Can you compare the function of veins in plants with anything else you know.

Veseljchak [2.6K]

hope it helps

please mark brainliest

7 0

3 years ago

Please solve this problem using dimensional analysis. Show your

Citrus2011 [14]

<h3>Answer:</h3>

4.3 miles

<h3>Explanation:</h3>

We are given;

Distance of 22,704 feet

We are required to determine the number of miles in 22,704 feet

To convert one unit to another we use conversion factors
Therefore, we need to know the suitable conversion factor.
That is, 1 mile/5,280 feet
Thus, to determine the number of miles we multiply the number of feet with the conversion factor.

That is;

= 22,704 feet × 1 mile/5,280 feet

= 4.3 miles

Therefore, there are 4.3 miles in 22,704 feet

5 0

3 years ago

How many electrons in an atom can have the following quantum

gavmur [86]

The answer for the following question is explained.

Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is one(1).

Explanation:

Here;

n represents the principal quantum number

l represents the Azimuthal quantum number

m represents magnetic quantum number

s represents spin quantum number

n = 5,

l = 2,

m = -2,

s = +1/2

Here, it implies 5d orbital.

In the 5d orbital, 10 electrons.

As the magnetic quantum number is -2, and so it can have 1 electron.

Therefore the number of electrons present with the values n = 5, l = 2, m = -2, s = +1/2 is one(1)

7 0

3 years ago

calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w

kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is $-22Jmole^-^1k^-^1$

(b) The normal boiling point of water (J·K−1·mol−1) is $-109Jmole^-^1K^-^1$

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole

Explanation:

Lets calculate

(a) - General equation -

$(\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p$ = $-5_m(\beta )+5_m(\alpha )$ = $-\frac{\Delta H}{T}$

$\alpha ,\beta$ → phases

ΔH → enthalpy of transition

T → temperature transition

$(\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p$ = $= -\frac{\Delta_fH}{T_f}$

= $\frac{-6.008kJ/mole}{273.15K}$ ( $\Delta_fH$ is the enthalpy of fusion of water)

= $-22Jmole^-^1k^-^1$

(b) $(\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}$

= $\frac{40.656kJ/mole}{373.15K}$ ( $\Delta_v_a_p_o_u_rH$ is the enthalpy of vaporization)

= $-109Jmole^-^1K^-^1$

$[\mu(l-5$ ° $C)-\mu(l,0$ ° $C)]$ = $[\mu(s-5$ ° $C)-\mu(s,0$ ° $C)]$ $=-S_m$ ΔT

$\mu(l,-5$ ° $C)-\mu(s,-5$ ° $C)=-Sm\DeltaT [\mu(l,0$

$\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)$

= 109J/mole

6 0

2 years ago

State the periodic law, and explain its relation to electron configuration. (Use Na and K in your explanation.)

mina [271]

Answer:

Explanation:

The period law state that when elements are listed in order of their atomic numbers, the elements fall into recurring groups, so that there is a recurrence of similar properties at regular intervals.

Na and K in the periodic table fall into the same group, this is because they both have one electrons in their outermost shell.

Na 11 -1s2 2s2 2p6 3s1

K 19 - 1s2 2s2 2p6 3s2 3p6 4s1

They share similar chemical and physical properties. Na and K are very reactive metals, they can loose/donate their outermost electron to non metals in other to attain stable octet state.

The form ionic compound when they react with non metals.

5 0

3 years ago