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2 years ago

Therefore, the product 0.5 × (–2) is

Mathematics

1 answer:

Savatey [412]2 years ago

6 0

Answer:

-1

Step-by-step explanation:

don't really have a step by step explanation but it was kinda easy if you just put it in the calculator

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Which fraction can be expressed as a repeating decimal?<br> A; 1/10<br> B; 1/4<br> C; 3/5<br> D; 7/9

Tju [1.3M]

Answer: The answer is D

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

519 divided by 6 and 915 divided by 7 and 439 divided by 7 and 812 divided by 9 which one does not have a two digit quotient.

Setler [38]

519/6=86.5

915/7=130.7142

439/7=62.7142

812/9=90.2222

so i think its the 1st on but i may be wrong.

5 0

3 years ago

Please help me out I just really hate math

Schach [20]

If a person gets flat commission of $60 for every $200 of profit then for $1000 profit the commission would be $300. For $1500 the commission would be $450.

5 0

3 years ago

Multiply.

Nady [450]

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Explanation:</h2>

Here we have the following expression:

$3\sqrt{22}\sqrt{58}\sqrt{18}$

So we need to simplify that radical expression. By property of radicals we know that:

$\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}$

So:

$3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}$

The prime factorization of 22968 is:

$22968=2^3\cdot 3^2\cdot11\cdot 29$

Hence:

$3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}$

By property:

$\sqrt[n]{a^n}=a$

So:

$3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}$

Finally:

$\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}$

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0

3 years ago

How do you write 5/20 as a percent?????

Maksim231197 [3]

Answer:

25%

Step-by-step explanation:

$\displaystyle \frac{5}{20} = \frac{1}{4} =$ 25%

I am joyous to assist you anytime.

3 0

3 years ago