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3 years ago

Graph the line x = -6 on the axes delta math

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

4 0

Answer:

Draw a vertical line on a graph, with the x-axis at -6

this line should be parallel to the y-axis, but shift to the left 6 units.

Step-by-step explanation:

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I need a solution<br><img src="https://tex.z-dn.net/?f=2log_%7Bx%7D25%20-%203%20log_%7B25%7Dx%20%3D%201" id="TexFormula1" title=

Korvikt [17]

Given
$2log_x(25)-3log_{25}(x)=1$

first, convert $2log_x(25)$ to base 25 to match the other term.
$2log_x(25)$
$=2log_{25}(25)/log_{25}(x)$
$=2*1/log_{25}(x)$

Substitute above identity into original equation:
$2/log_{25}(x)-3log_{25}(x)=1$

Use substiution $u=log_{25}(x)$
above equation becomes
2/u-3u=1
multiply by u and solve for u:
$3u^2+u-2=0$
=> u=2/3 or u=-1

case A:. u=2/3 =>
$log_{25}(x)=2/3 => 25^{2/3}=x$ =>
$x=25^{2/3} =8.54987973338348 (approx.)$

case B: u=-1 =>
$log_25(x)=-1$
which does not give a real solution, so reject.

See graph below for confirmation of solution.

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4 years ago

4 Which statement about a sphere is true?O The length of the diameter of a sphere is two times the length of the radius of the s

frosja888 [35]

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3 years ago

Read 2 more answers

A college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student i

kolbaska11 [484]

Answer:

Yes, Students are scoring above 2222 on the math portion of the exam.

Step-by-step explanation:

We are given that a college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student is ready for college-level mathematics i.e., population mean is 22.

Null Hypothesis, $H_0$ : $\mu$ = 22 {Students are scoring equal to 2222 on the math portion of the exam}

Alternate Hypothesis, $H_0$ : $\mu$ > 22 {Students are scoring above 2222 on the math portion of the exam}

Also, a random sample of 150 students who completed this core set of courses results in a mean math score of 22.7 on the college entrance exam with a standard deviation of 3.93 i.e.;

Sample mean, $Xbar$ = 22.7 and Sample standard deviation, s = 3.93

The Test statistics is given by;

Z = $\frac{Xbar -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

Test Statistics = $\frac{22.7 -22}{\frac{3.93}{\sqrt{150} } }$ ~ $t_1_4_9$

= 2.1815

Since, we are not given with the significance level, so we assume it to be 5%. At 5% significance level t table gives critical value of 1.6578 at 149 degree of freedom. Since our test statistics is more than the critical value so we reject null hypothesis as our test statistics fall in the rejection region.

Therefore, we conclude that Students are scoring above 2222 on the math portion of the exam.

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