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2 years ago

Graph the line x = -6 on the axes delta math

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

4 0

Answer:

Draw a vertical line on a graph, with the x-axis at -6

this line should be parallel to the y-axis, but shift to the left 6 units.

Step-by-step explanation:

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maxonik [38]

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3 years ago

Read 2 more answers

Evaluate x(-y + z) for x = 5, y = 9, and z = 1.

NemiM [27]

Answer:

-20

Step-by-step explanation:

x(-y+z) [Switch in the values]

=5(-5+1) [Use distributive property and multiply]

=(-25)+5 [do the basic math]

=(-20) [final answer]

6 0

3 years ago

Read 2 more answers

Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. Write an equation for

vivado [14]

Answer:

The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ .

Step-by-step explanation:

Given as :

The initial level of water in river = 34 feet

The rate of receding water level = 0.5 foot per day

Or, The rate of percentage of receding water level = 50 % per day

Let the level of water after d days = L

Now,

The level of water after d days = initial level of water × ( $(1-\dfrac{\textrm Rate}{100})^{Time}$

I.e L = 34 × ( $(1-\dfrac{\textrm 50}{100})^{d}$

∴ L = 34 × $(0.5)^{d}$

Hence The equation to represent the rate of receding water level is L = 34 $(0.5)^{d}$ . Answer

5 0

3 years ago

Please help Person with the right answer I will mark Brainlyist

e-lub [12.9K]

Answer:

The equation in the standard form is

$y+2x=5$

Step-by-step explanation:

Given the points

(6, -7)

(4, -3)

Finding the slope between (6, -7) and (4, -3)

$\left(x_1,\:y_1\right)=\left(6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(4,\:-3\right)$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-3-\left(-7\right)}{4-6}$

$m=-2$

As the point-slope form is defined as

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -2 and the point (6, -7)

$y-y_1=m\left(x-x_1\right)$

$y-\left(-7\right)=-2\left(x-6\right)$

Writing the equation in the standard form form

As we know that the equation in the standard form is

$Ax+By=C$

where x and y are variables and A, B and C are constants

converting the equation in standard form

$y-\left(-7\right)=-2\left(x-6\right)$

$y+7=-2\left(x-6\right)$

subtract 7 from both sides

$y+7-7=-2\left(x-6\right)-7$

$y=-2x+5$

$y+2x=5$

Therefore, the equation in the standard form is

$y+2x=5$

7 0

3 years ago

What is a correct equation for the line passing through the point (-2,1) and having slope m=1/2

frez [133]

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We ahve the slope m = 1/2 and the point (-2, 1). Substitute:

$y-1=\dfrac{1}{2}(x-(-2))$

$y-1=\dfrac{1}{2}(x+2)$ - point-slope form

Covert to the slope-intercept form (y = mx + b):

$y-1=\dfrac{1}{2}(x+2)$ use the distributive property

$y-1=\dfrac{1}{2}x+1$ add 1 to both sides

$y=\dfrac{1}{2}x+2$ - slope-intercept form

Convert to the standard form (Ax + By = C):

$y=\dfrac{1}{2}x+2$ multiply both sides by 2

$2y=x+4$ subtract x from both sides

$-x+2y=4$ change the signs

$x-2y=-4$ - standard form

Convert to the general form (Ax+By+C=0):

$x-2y=-4$ add 4 to both sides

$x-2y+4=0$ - general form

5 0

3 years ago