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Keith_Richards [23]
2 years ago
14

For which values of x does each expression make sense? √(-2x)^2

Mathematics
1 answer:
cricket20 [7]2 years ago
7 0

We want to see for which values of x does the rational expression make sense. We will see that the expression makes sense for x ≤ 0

We know that the argument of a square root can only be a real number equal to or larger than zero.

In this case, we have the expression:

\sqrt{(-2x)^2} = (\sqrt{-2x} )^2

One would want to directly cancel the square root with the 2 exponent, but we can't do that, because in the right-side expression we would have a complex number if the argument is smaller than zero.

The first thing we need to do is to make the argument equal or larger than zero:

-2x ≥ 0

x ≤ 0/-2

x ≤ 0

So the given expression only makes sense for x ≤ 0

If you want to learn more about rational expressions, you can read:

brainly.com/question/18545256

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<em>ju</em><em>st</em><em> </em><em>subst</em><em>itute</em><em> </em><em>the</em><em> </em><em>va</em><em>lues</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>and </em><em>y</em><em> </em><em>int</em><em>o</em><em> </em><em>th</em><em>e</em><em> </em><em>exp</em><em>ression</em><em> </em><em>to</em><em> </em><em>get</em>

<em>4</em><em>(</em><em>2</em><em>)</em><em>+</em><em>1</em><em> </em><em>/</em><em>3</em><em>(</em><em>3</em><em>)</em><em>^</em><em>2</em>

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