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laiz [17]
2 years ago
10

Conner earns 24$ working every 1.5 12 blank

Mathematics
1 answer:
RoseWind [281]2 years ago
5 0

Answer: That makes no sense. Maybe did your copy and paste corrupt? Or mistyped the question? Get back to me and I’ll help!!

Step-by-step explanation:

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Can someone explain this to me like do I do division so get the answer or?
Brrunno [24]

Answer: You could either multiply or divide. I reccommend asking for help with your mom or teacher. Hope this helps a bit.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A pump fills a pool at a constant rate. At the end of 21 minutes it has filled 7 gallons of water. Which table represents the re
likoan [24]

Answer:

B.

Step-by-step explanation:

cuz you take 21 divide by 7 equals 3. 33 divided by 3 equals 11

i hope this is right!!! :)

6 0
2 years ago
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
To find the distance across a lake, a
Nesterboy [21]

The distance across the lake, a is 611 yards

<h3>Right angle triangle:</h3>

Right angle triangle have one of its angles as 90 degrees. Therefore, the side a can be found using trigonometric ratios,

Therefore,

tan 47° = opposite / adjacent

tan 47° = a / 570

cross multiply

a = 570 tan 47°

a = 570 × 1.07236871002

a = 611.250164714

a = 611 yards

learn more on right triangle here: brainly.com/question/18450490

6 0
2 years ago
Read 2 more answers
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
2 years ago
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