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BartSMP [9]
3 years ago
15

About how many years ago did Jesus live A.10,000 B. 5,000 C. 2,000 D. 1,000

Mathematics
1 answer:
vredina [299]3 years ago
5 0

Jesus was born in 4 BC (more or less) and live to be 33 years old, which means His death was around 29 AD (more or less). That was precisely, 1992 years ago

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What is the slope-intercept form of the equation of the line containing the points (−2, 4) and (6, 0)?
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The slope-intercept form of the equation of the line containing the points (−2, 4) and (6, 0) will be y =0.5 x+ 5.

<h3>What is the slope?</h3>

A numerical assessment of a line's angle relative to the ground is known as the slope.

The inclination of any line, ray, or line segment is the fraction of the perpendicular to the horizontal distance between any two positions on it.

The slope of the line is found as;

\rm m = \frac{y_2-y_1}{x_2-x_1} \\\\ m = \frac{0-4}{6-(-2)} \\\\ m = \frac{-4}{8} \\\\ m = \frac{-1}{2}

The standard line equation is;

y-y₁=m(x-x₁)

\rm y-4= \frac{-1}{2}(x-(-2)) \\\\ 2y-8 = x+2 \\\\ 2y =x+10 \\\\ y = 0.5 x + 5

Hence, the slope-intercept form of the equation of the line containing the points (−2, 4) and (6, 0) will be y =0.5 x+ 5.

To learn more about the slope, refer to the link;

brainly.com/question/3605446

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6 0
2 years ago
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Step-by-step explanation:

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