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BartSMP [9]
3 years ago
15

About how many years ago did Jesus live A.10,000 B. 5,000 C. 2,000 D. 1,000

Mathematics
1 answer:
vredina [299]3 years ago
5 0

Jesus was born in 4 BC (more or less) and live to be 33 years old, which means His death was around 29 AD (more or less). That was precisely, 1992 years ago

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Find the slope of the line that passes through (10, 8) and (1, 1).
Nana76 [90]

Answer:

2/3

Step-by-step explanation:

the formula to find slope is y1-y2/x1-x2.

The ordered pairs are (10,8) and (1,1)

                                     (x, y).        (x, y)

So it would be: 8-1 OVER 10-1

=6/9 which simplifies to 2/3

so your slope would be 2/3

5 0
3 years ago
Evaluate the function f\left(x\right)=5x+2\mid11-5x\mid-4f(x)=5x+2∣11−5x∣−4 for x = -5.
Anestetic [448]

Answer:

f\left(5\right) = 43

Step-by-step explanation:

Given

f\left(x\right)=5x+2\mid11-5x\mid-4

Required

Solve for x = -5

This implies that we substitute -5 for x in f\left(x\right)=5x+2\mid11-5x\mid-4

f\left(5\right)=5(-5)+2\mid11-5(-5)\mid-4

Open all brackets

f\left(5\right) = -25+2\mid11+25\mid-4

f\left(5\right) = -25+2\mid36\mid-4

Absolute value of 36 is 36; Wo, we have:

f\left(5\right) = -25+2*36-4

f\left(5\right) = -25+72-4

f\left(5\right) = 43

7 0
3 years ago
Find the intersection points of the linear and quadratic functions shown below f(x)=2x-5 g(x)= x2+2x-21
Mice21 [21]

Answer:

(-4,-13) and (4,3) the intersection points.

Step-by-step explanation:

Intersection point of two functions is a common point which satisfies both the functions.

Given functions are,

f(x)=2x-5

g(x)=x^2+2x-21

For a common point of these functions,

f(x)=g(x)

2x-5=x^2+2x-21

-5=x^2-21

0=x^2-16

x^2=16

x=-4,4

For x=-4,

f(-4)=g(-4)=2(-4)-5

                       =-13

For x=4,

f(4)=g(4)=2(4)-5

                  =3

Therefore, (-4,-13) and (4,3) the intersection points.

3 0
3 years ago
I need help with this points if right
fomenos

Answer:

A

Step-by-step explanation:

90-49=41

41-3=38

49+(38+3)=90

6 0
3 years ago
How to solve approximate square roots
Murljashka [212]
Just follow this operation.
Find the two perfectly squared factors the multiple to your number.
Take the square root of those perfect factors then multiple them.

5 0
3 years ago
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