Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Answer:
C. Atom 3
Explanation:
I'm sorry if I answered this late, but hope this helps! :D
Answer:
KE = PE at half the table Height:
Explanation
AT ANY POINT IN THE BOOK'S FALL,
TOTAL E = PE +KE
THE TOTAL E IS CONSTANT
Before the book is pushed off, the total energy is potential
TOT E=PE =MGH
BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC
TOT=KE = MVXV/2
WHEN KE = PE
KE+PE =<u> MGH (STARTING ENERGY SINCE E IS CONSERVED)</u>
<u>OR PE+ PE = MGH</u>
<u>OR MGH' + MGH' =MGH</u>
<u>OR 2H' =</u>H
H' (NEW HEIGHT) =H/2
: Atmospheric Carbon Dioxide. The global average atmospheric carbon dioxide in 2017 was 405.0 parts per million (ppm for short), with a range of uncertainty of plus or minus 0.1 ppm. Carbon dioxide levels today are higher than at any point in at least the past 800,000 years.