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OleMash [197]
2 years ago
8

Identify the following elements based on the information provided:

Chemistry
1 answer:
leonid [27]2 years ago
5 0

Answer:

answer

Explanation:

answer

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Describe the heart and it’s function
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Answer:

The human heart is an organ that pumps blood throughout the body via the circulatory system, supplying oxygen and nutrients to the tissues and removing carbon dioxide and other wastes.

Explanation:

Hope this helped! Good luck on whatever it is you're working on!

8 0
3 years ago
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An object has a mass of 441 g and a volume of 10cm3
expeople1 [14]

Answer:

44.1g/cm3

Explanation:

d=m/v

=441/10

=44.1 g/cm3

3 0
3 years ago
Explain The relationship between engineering science and technology
erik [133]


The Difference Between Science, Engineering, and Technology. Science is the study of the natural world as it is; engineering is creating new tools, devices, and processes based on scientific knowledge; technology is the sum total of all the engineered tools, devices and processes available.
5 0
3 years ago
How many calories are required to heat 867 g of water from 13°c to 87°c?
skelet666 [1.2K]
64158 calories is required
5 0
3 years ago
What mass of NaNO3 must be dissolved to make 838mL of a 1.25 M solution
denis-greek [22]

Answer:

89.04 g of NaNO₃.

Explanation:

We'll begin by converting 838 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

838 mL = 838 mL × 1 L / 1000 mL

838 mL = 0.838 L

Next, we shall determine the number of mole of NaNO₃ in the solution. This can be obtained as follow:

Volume = 0.838 L

Molarity = 1.25 M

Mole of NaNO₃ =?

Mole = Molarity × volume

Mole of NaNO₃ = 1.25 × 0.838

Mole of NaNO₃ = 1.0475 mole

Finally, we shall determine the mass of NaNO₃ needed to prepare the solution. This can be obtained as follow:

Mole of NaNO₃ = 1.0475 mole

Molar mass of NaNO₃ = 23 + 14 + (16×3)

= 23 + 14 + 48

= 85 g/mol

Mass of NaNO₃ =?

Mass = mole × molar mass

Mass of NaNO₃ = 1.0475 × 85

Mass of NaNO₃ = 89.04 g

Therefore, 89.04 g of NaNO₃ is needed to prepare the solution.

4 0
3 years ago
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