Answer:
longing for social inclusion.
Explanation:
Ross here is longing for social inclusion.
He decides to campaign for the his fraternity brother not by choice or will but by peer pressure and social inclusion because most of the students campaigned for Henry so he supports Henry as well. Moreover, he did not be feel left out and he did not have a clear preference as well.
The inner planets are closer to the Sun and are smaller and rockier. ... The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars.Apr 23, 2014
Answer: 33.7Ω
Explanation:
Since there are two resistors connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
R1 = 10Ω
R2 = 23.7Ω
Hence, Rtotal = 10Ω + 23.7Ω
Rtotal = 33.7Ω
Thus, the combined resistance for two resistors is 33.7Ω
A = Delta v/Delta t
Delta v = 25 - 0 = 25
Delta t = 30
25/30 = 5/6 = 1.66 repeating
Complete Question
Suppose you have three identical metal spheres, A, B, and C. Initially sphere A carries a charge q and the others are uncharged. Sphere A is brought in contact with sphere B, and then the two are separated. Spheres CC and BB are then brought in contact and separated. Finally spheres AA and CC are brought in contact and then separated. What is the final charge on the sphere B, in terms of q?
a. 3/8q
b. 1/4q
c. 3/4q
d. q
e. 5/8q
f. 1/3q
g.1/2q
h. 0
Answer:
The correct option is b
Explanation:
From the question we are told that
The charge carried by A is q C
The charge carried by B is 0 C
The charge carried by C is 0 C
When A and B are brought close and then separated the charge carried by A and B is mathematically evaluated as
![\frac{ 0 + q}{2} = \frac{q}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%200%20%2B%20q%7D%7B2%7D%20%3D%20%20%20%5Cfrac%7Bq%7D%7B2%7D)
When C and B are brought close and then separated the charge carried by C and B is mathematically evaluated as
![\frac{0 + \frac{q}{2} }{2} = \frac{q}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B0%20%2B%20%5Cfrac%7Bq%7D%7B2%7D%20%7D%7B2%7D%20%20%3D%20%5Cfrac%7Bq%7D%7B4%7D)
When C and A are brought close and then separated the charge carried by C and A is mathematically evaluated as
![\frac{\frac{q}{4} + \frac{q}{2} }{2} = \frac{3q}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7Bq%7D%7B4%7D%20%2B%20%20%5Cfrac%7Bq%7D%7B2%7D%20%7D%7B2%7D%20%20%20%3D%20%5Cfrac%7B3q%7D%7B8%7D)
Looking at these calculation we can see that the charge carried by B is
![\frac{q}{4} C](https://tex.z-dn.net/?f=%5Cfrac%7Bq%7D%7B4%7D%20C)