Answer:
a=1.024m/s
t=15.62s
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X (2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 4 above equations and use algebra to solve
for this problem
Vf=16m/s
Vo=0m/s, the cart starts from the rest
X=125m
we can use the ecuation number tow to calculate the acceleration
{Vf^{2}-Vo^2}/{2.a} =X
{Vf^{2}-Vo^2}/{2.x} =a
{16^{2}-0^2}/{2(125)} =a
a=1.024m/s
to calculate the time we can use the ecuation number 1
Vf=Vo+a.t
t=(Vf-Vo)/a
t=(16-0)/1.024
t=15.62s
It can be observed without changing the identity of the object.
