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Irina-Kira [14]
1 year ago
9

What is the isomers for C6H3(ch3)2cl?

Chemistry
1 answer:
julia-pushkina [17]1 year ago
6 0

Explanation:

Assume that the set of conditionals is true. Use the Law of Syllogejjsnsjbsjxjxjjdjwvsgosbsgismebgsisbsgjsnsgism to

write a true conditional.ufzigo

8. If two numbers are odd, the sum of the numbers is even. If a number is

even, then the number is divisiblhagsal

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Of the choices, which metal element would be the most reactive? (Please explain why the answer is the answer).
mart [117]

Answer:

sulfur

Explanation:

sulfur because it have unknown metal

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A.<br> B.<br> C.<br> D.<br><br> what could be the correct answer? Help me please
AlladinOne [14]

Answer:

A

Explanation:

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3 years ago
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What is the percent composition of hydrogen in vinegar (CH3COOH)?​
barxatty [35]

Answer:

                      %H  = 6.72 %

Explanation:

                   Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.

So,

Percent composition of Hydrogen will be given as,

         %H  =  Total mass of H / Molecular Mass of Acetic Acid × 100

So,

Total Mass of H  =  1.01 × 4 = 4.04 g

Molecular Mass of Acetic acid  =  60.052 g/mol

Putting values in above formula,

         %H  =  4.04 g/mol ÷ 60.052 g/mol × 100

         %H  = 6.72 %

6 0
3 years ago
2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?​
Sophie [7]
<h3>Answer:</h3>

\displaystyle 0.5 \ mol \ CO_2

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                        \displaystyle 0.5 \ mol \ CO_2
7 0
2 years ago
Please help, need asap, just tell me where they go​
Lostsunrise [7]

Answer:

1 to 2 3 to 6

Explanation:

5 0
2 years ago
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