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Anit [1.1K]
3 years ago
7

PLEASE HELP!! I WILL MARK THE 1st ONE BRAINLIEST!

Chemistry
1 answer:
allsm [11]3 years ago
6 0

Answer:

I hope you do well on the test good luck

Explanation:

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In the context of small molecules with similar molar masses, arrange these intermolecular forces by strength (hydrogen bonding -
Katarina [22]
<h2>Answer:</h2>

Arrangement of inter molecular forces from strongest to weakest.

  • Hydrogen bonding
  • Dipole-dipole interactions
  • London dispersion forces.
<h3>Explanation:</h3>

Intermolecular forces are defined as the attractive forces between two molecules due to some polar sides of molecules. They can be between nonpolar molecules.

Hydrogen bonding is a type of dipole dipole interaction between the positive charge hydrogen ion and the slightly negative pole of a molecule. For example H---O bonding between water molecules.

Dipole dipole interactions are also attractive interactions between the slightly positive head of one molecule and the negative pole of other molecules.

But they are weaker than hydrogen bonding.

London dispersion forces are temporary interactions caused due to electronic dispersion in atoms of two molecules placed together. They are usually in nonpolar molecules like F2, I2. they are weakest interactions.

5 0
3 years ago
Which of the following processes have a ΔS &lt; 0? Which of the following processes have a ΔS &lt; 0? carbon dioxide(g) → carbon
Umnica [9.8K]

Answer:

All of the above processes have a ΔS < 0.

Explanation:

ΔS represents change in entropy of a system. Entropy refers to the degree of disorderliness of a system.

The question requests us to identify the process that has a negative change of entropy.

carbon dioxide(g) → carbon dioxide(s)

There is  a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.

water freezes

There is  a change in state from liquid to solid. Solid particles are more ordered than liquid particles so this is a negative change in entropy.

propanol (g, at 555 K) → propanol (g, at 400 K)

Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.

This reaction highlights a drop in temperature which means a negative change in entropy.

methyl alcohol condenses

Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.

6 0
3 years ago
Equal amounts of four gases are placed in identical containers at the temperatures that are noted below. Samples of Gases at Dif
Alborosie
Answer : S)  33.2 °C

Explanation : When the equal amounts of gases are placed in identical containers but subjected to different temperatures would exert pressure in different amount which will in turn increase the rate of collision between the molecules of gas.

So, when the temperature is increased to maximum greater amount of force would be exerted and the gas molecules will collide with a larger force. Hence the answer will be as the highest temperature i.e. 33.2 °C
4 0
3 years ago
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