Question

Dominique needs to solve the system of equations by graphing. Which statement is true about the system? 2 x minus 3 y = 12. Y = negative three-fifths x 2. Both equations are in slope-intercept form. Neither equation is in slope-intercept form. The first equation is y = two-thirds x minus 4 when written in slope-intercept form. The second equation is 3 x 5 y = 10 when written in slope-intercept form.

Answer 1

Answer:

c

Step-by-step explanation:

Answer 2

Answer:

Option C) The first equation is y= 2/3x-4 when written in slope-intercept form .

Step-by-step explanation:

We have

$2x - 3y = 12 \: > \: first \: equation$

The first equation is in Standard form .

Convert to slope Intercept form .

Isolate the Variable y .

$3y = 2x - 12$

Divide by 3 both sides .

$y = \frac{2}{3} x - 4$

$y = - \frac{3}{5} x + 2 > second \: equation$

The second equation is in slope Intercept form .

Convert to standard form

Multiply by 5 both sides to remove the fraction .

$5y = - 3x + 10$

$3x + 5y = 10$

Verify each statement :-

• case A) Both equations are in slope-intercept form.

• False

• Because only the second equation is in slope -intercept form

• case B) Neither equation is in slope-intercept form .

• False

• Because, the second equation is in slope -intercept form

• case C) The first equation is y= 2/3x-4 when written in slope-intercept form

• True (see the procedure)

• case D)The second equation is 3x+5y=10 when written in slope-intercept form.

• False

• Because, the second equation is 3x+5y=10 when written in standard form .

I hope this helps you !!