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8_murik_8 [283]
2 years ago
12

Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb

er: cal=m*deltaT
(WRITE THE WORK!/Give explanation.)
Physics
1 answer:
GuDViN [60]2 years ago
7 0

Answer:

Q = 12540  J

Explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

It is heated from 0 degrees Celsius to 60 degrees Celsius.

We need to find the energy required to heat the water. The formula use to find it as follows :

Q=mc\Delta T

Where c is the specific heat of water, c = 4.18 J/g°C

Put all the values,

Q=50\times 4.18\times (60-0)\\Q=12540\ J

So, 12540 J of energy is used to heat the water.

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Which image shows the difference between the speed of molecules in hot and cold water? Explain your answer choice.
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A very long solenoid with a circular cross section and radius r1= 1.30 cm with ns= 260 turns/cm lies inside a short coil of radi
allochka39001 [22]

Answer:

0.00851 volts

Explanation:

radius r1= 1.30 cm with ns= 260 turns/cm

radius r2= 4.60 cm and Nc= 23 turns

constant rate from zero to Is= 1.90 A

time interval of 88.0 ms

Area of the solenoid

A_1=\pi*r_1^2

=\pi*0.013^2

A_1=5.31*10^-^4 m^2

Mututal Inductance

M=uo*n*N*A1

M=(4\pi*10^-^7)*23*(260*10^2)*(5.31*10^-^4)

M=3.99*10^-^4 H

a)

EMF induced in the outer coil

E=M(dIs/dt)

E=(3.99*10^-^4)*(1.9/88*10^-^3)

E=0.00861 Volts

5 0
3 years ago
A loaded 320 kg toboggan is traveling on smooth horizontal snow at 4.60 m/s when it suddenly comes to a rough region. The region
MariettaO [177]

Answer:

367.04 N

Explanation:

Frictional force = mass of the toboggan×deceleration caused by the rough region

Fr = m×ar....................... Equation 1

Where Fr = Average frictional force, m = mass of loaded toboggan, ar = deceleration cause by the rough region.

We can calculate for ar using the formula below

v² = u²+2ars................... Equation 2

make ar the subject of the equation

ar = (v²-u²)/2s.................. Equation 3

Where v = final velocity of the toboggan, u = initial velocity of the toboggan, s = distance or length of the rough region

Given: v = 1.2 m/s, u = 4.6 m/s, s = 8.6 m

Substitute into equation 3

ar = (1.2²-4.6²)/(2×8.6)

ar = (1.44-21.16)/17.2

ar = -19.72/17.2

ar = -1.147 m/s²

Also given: m = 320 kg

Substitute into equation 1

Fr = 320(-1.147)

Fr = -367.04 N

Note: The negative sign tells that the frictional force opposes the motion of the toboggan

6 0
3 years ago
A car, travelling at a speed of 30 m/s in a straight line, brakes and decelerates at a uniform rate of 2 m/s2. How much further
AURORKA [14]

Answer:

You are finding acceleration, so it would be 15 m/s2

Explanation:

30 divided by 2

3 0
2 years ago
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