All categories

3 years ago

Compare and contrast the shape and volume of each state of matter

Physics

1 answer:

Komok [63]3 years ago

8 0

Answer:

<em><u>Solid</u> is the state in which matter maintains a fixed volume and shape; liquid is the state in which matter adapts to the shape of its container but varies only slightly in volume; and gas is the state in which matter expands to occupy the volume and shape of its container.</em>

You might be interested in

What is the coefficient of Static Friction if It Takes 44N of force to move A Box that Weight 86N ? A, 0.78 B 0.51. C.0.78N D. 0

levacccp [35]

Answer:

1. What is the force of friction between a block of ice that

weighs 930 N and the ground if m = .12?

F fr £ µ sF N

F fr = µ kF N

F = ma

F N = 930 N

µ s = .12

F fr =µ kF N = (930)(.12) = 111.6 N = 110 N

(Table of contents)

2. What is the coefficient of static friction if it takes 34 N of

force to move a box that weighs 67 N?

F N = 67 N

µ s = ?

F fr =34 N

F fr = µ kF N

34 = µ k(67)

µ s = .507 = .51

(Table of contents)

3. A box takes 350 N to start moving when the coefficient of

static friction is .35. What is the weight of the box?

F N = ?????

µ s = .35

F fr =350 N

F fr = µ kF N

350 = (.35)F N

F N = 1000 N = 1.0 x 10 3 N

(Table of contents)

4. A car has a mass of 1020 Kg and has a coefficient of

friction between the ground and its tires of .85. What force of

friction can it exert on the ground? What is the maximum

acceleration of this car? In what minimum distance could it

stop from 27 m/s?

First find the normal force which is the weight in this

case:

F = ma = (1020 kg)(9.80 m/s/s) = 9996 N = F N

Then use the Friction formula to find the frictional

force with the ground:

F fr = = (.85)(9996 N) = 8496.6 N = 8500 N

Now we can find the acceleration. The Force of

friction is what speeds up the car, so

F = ma

8496.6 N = (1020 kg)(a)

a = 8.33 m/s/s = 8.3 m/s/s

So now we need to solve a cute linear kinematics

problem:

x = ?????

v i = 27

v f = 0

a = -8.33 m/s/s (slowing down)

t = don't care

Use vf 2 = vi 2 + 2ax:

0 2 = (27) 2 + 2(-8.33 m/s/s)s

x = 43.76 m = 44 m

(Table of contents)

5. Clarice moves a 800. gram set of weights by applying a

force of 1.2 N. What is the coefficient of friction?

m = 800. g = .800 kg (divide by 1000)

First find the normal force which is the weight in this

case:

F = ma = (.800 kg)(9.80 m/s/s) = 7.84 N = F N

Next - apply the force of friction formula:

F fr = µ kF N

1.2 N = µk (7.84 N)

µ k = .15306 = .15

(Table of contents)

Explanation:

Note that is not an answer that is guide

thanks po

hope it help ❤️

6 0

3 years ago

Which gaseous giants did renaissance scientists such as galileo know about? select two options. jupiter mars neptune saturn uran

maksim [4K]

Answer:

Jupiter and Saturn

Please Mark Brainliest If This Helped!

5 0

3 years ago

. Consider a fully extended arm that is rotating about the shoulder such that with a shoulder-to-hand length of 30 cm. If the ar

Rainbow [258]

Answer:

13.309 m/s²

Explanation:

Length from shoulder to hand, l = 30 cm = 0.3 m

initial velocity, u = 1 m/s

final velocity, v = 2.5 m/s

time, t = 3 s

Let the tangential acceleration is a.

by using first equation of motion

v = u + at

2.5 = 1 + 3 a

a = 0.5 m/s²

Let the centripetal acceleration is a'.

a' = v'²/l

a' = 2 x 2 / 0.3

a' = 13.3 m/s²

The tangential acceleration and the centripetal acceleration are both perpendicular to each other. So, the net acceleration is given by

$A=\sqrt{a^{2}+a'^{2}}$

$A=\sqrt{0.5^{2}+13.3^{2}}$

A = 13.309 m/s²

3 0

4 years ago

5. The table shows the total vertical distance a free-falling body travels for each second it falls. About how far does the free

ratelena [41]

Answer:

a. 44 m

Explanation:

We don't have the table but we can still answer since the motion is a free-fall motion.

First of all, we calculate the velocity of the body at time t = 4 s, with the equation

$u'=u+gt$

where

u = 0 is the initial velocity

g = 9.8 m/s^2 is the acceleration of gravity (we take downward as positive direction)

t is the time

Using t = 4 s,

$u'=0+(9.8)(4)=39.2 m/s$

Now we can calculate the distance covered during the time t = 4 s and t = 5 s using the other suvat equation

$s=u'\Delta t+\frac{1}{2}g\Delta t^2$

where

$\Delta t = 5-4=1s$ is the time interval we are considering. Substituting values,

$s=(39.2)(1)+\frac{1}{2}(9.8)(1)^2=44 m$

4 0

3 years ago

Jack and Linda are two friends who live within 10 miles of each other, but they live at different elevations. Jack lives near se

Marta_Voda [28]

The answer is C since the higher up you go the colder it gets which is why Linda will experience colder climates.

7 0

3 years ago

Read 2 more answers