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rosijanka [135]
3 years ago
8

Impulse: A batter applies an average force of 8000 N to a baseball for 1.1 ms. What is the magnitude of the impulse delivered to

the baseball by the bat
Physics
1 answer:
fiasKO [112]3 years ago
5 0

The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

<h3>Impulse experienced by objects</h3>

The impulse experienced by any object is equal to the change in the momentum of the object.

The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.

J = Ft

where;

  • F is applied force = 8000 N
  • t is time, = 1.1 ms

J = (8000) x (1.1 x 10⁻³)

J = 8.8 Ns

Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

Learn more about impulse here: brainly.com/question/229647

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Friction is a force that opposes motion.

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The three stages of a train route took 1 hour ,2 hours ,and 4 hours . The first two stages were 80km and 200km of the train aver
luda_lava [24]

Answer:

the third stage was 480 km long

Explanation:

Stage 1:

Time = 1 hours

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Stage 2:

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Speed = 200km

Stage 3:

Time =  4 hours

Let the Distance at the stage 3 be x

Average speed of the train route = 100 km/h

So

\frac{ \text{speed at stage 1} + \text{speed at stage 2} + \text{speed at stage 3}}{3} = 0

\frac{ \text{speed at stage 1} + \text{speed at stage 2} + \text{speed at stage 3}}{3} = 100

Lets find the speed at stage 1

Speed =  \frac{Distance }{Time}

Speed =  \frac{80}{1}

Speed 1= 80 km/hr

The speed at stage 2

Speed =  \frac{Distance }{Time}

Speed =  \frac{200}{2}

Speed 2  = 100 km/hr

The speed at stage 3

Speed =  \frac{Distance }{Time}

Speed =  \frac{x}{4}

Speed 3  = \frac{x}{4}

we kow that average is ,

\frac{ \text{speed 1} + \text{speed 2} + \text{speed 3}}{3} = 100

\frac{ 80 + 100+ \frac{x}{4} }{3} = 100

\frac{ 180 + \frac{x}{4} }{3} = 100

\frac{ \frac{720 +x}{4} }{3} = 100

\frac{720 +x}{4} \times \frac{1}{3} = 100

\frac{720 +x}{12} = 100

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x = 480

6 0
3 years ago
A downward force of magnitude 5 n is exerted on the book by the force of.
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Answer:

A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...

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A charged particle of mass 0.0050 kg is subjected to a 5.0 T magnetic field which acts at a right angle to its motion. If the pa
Irina18 [472]

Answer:

0.01 C

Explanation:

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Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф =  angle

Since the charged particle noves in a circle,

F = mv²/r................. Equation 2

Where m = mass of the particle, v = velocity of the particle, r = radius of the  circle

Substitute equation 2 into equation 1

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make q the subject of the equation

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Substitute these values into equation 3

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q = 0.01/(1)

q = 0.01 C

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3 years ago
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