Answer:
x = 3
AB = 16
Step-by-step explanation:
Given: AM = 8, AB = 5x +1 and M is the midpoint of AB, the AM = MB
AB = 2AM
5x+1 = 2(8)
5x + 1 = 16
x = 16 - 1
5x = 15
x = 15/5
x = 3
Hence the value of x is 3
Since AB = 5x+1
AB = 5(3) + 1
AB = 15 + 1
AB = 16
Answer:
the probability that an individual, selected at random, will score below the mean on any normally distributed characteristic is just about 0.5.
Step-by-step explanation:
This probability in normal distribution corresponds to z-score of 0. Using normal distribution tables.
P(z < 0) = 1 - P(z ≥ 0) = 1 - 0.5 = 0.5
Which is very logical, to score below the mean on a normal distribution, the probability is just less than 0.5.
Not sure I understand this but
5x+2=0
5x = -2
x = -2/5
Or
x = -.4
<span>Just multiply both sides by 5</span>
Mari and Kai's test scores are shown below: Mari: 72, 80, 90, 73, 74, 90 Kai: 56, 63, 70, 100, 32, 23 If Kai and Mari both got a
mezya [45]
Answer:
A. Kai
Step-by-step explanation:
1st Step - find the average test scores for Mari and Kai
1st Step - find the average test scores for Mari and Kai
Mari: 72 + 80 + 90 + 73 + 74 + 90 = 479
479 ÷ 6 (total number of tests) = 79.8 (Average test score for Mari)
Kai: 56 + 63 + 70 + 100 + 32 + 23 = 344
344 ÷ 6 (total number of tests) = 57.3 (Average test score for Kai)
2nd Step - Now each student got a 100 on the next test (the 7th test). So add 100 to the initial total.
Mari: 479 + 100 = 579
579 ÷ 7 (new total number of tests) = 82.7 (New average test score for Mari)
Kai: 344 + 100 = 444
444 ÷ 7 (new total number of tests) = 63.4 (New average test score for Kai)
3rd Step - find the difference between Mari's test scores. then find the difference between Kai's test scores to see who will have the greatest increase in math grade.
Mari: 82.7 - 79.8 = 2.9
Kai: 63.4 - 57.3 = 6.1
6.1 is greater than 2.9
