Squared root of -100 = ____ + ____^i
1 answer:
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We have altitude h to side AB and AB=h, i.e. the altitude is congruent to the side it goes to.
That's all kinds of triangles. One way to see them is using two horizontal parallel lines h apart, the bottom one with a base AB=h somewhere on it. Then any C on the top line makes a triangle ABC with altitude h=AB.
Let's go through the choices.
I. ABC could be a right triangle. That's TRUE.
We could have the isoscleles right triangle, C directly above B, so AC is the leg and an altitude, AB=AC and B is the right angle.
II. Angle C cannot be a right angle. That's TRUE.
The biggest angle C can be is when it's over the midpoint of AB, so if AB=2, h=2, and
so
III. Angle C could be less than 45 degrees. That's TRUE.
As long as C stays on our top parallel, we can make it as acute as we like by going farther away from AB.
All true. Hmmm.
Answer:
The area of the triangle is
Step-by-step explanation:
Given
Triangle VWU
Required
Determine the Area of the Triangle
First, we'll solve for the third angle
Angles in a triangle when added equals 180; So
Next is to determine the length of VW using Sine Law which goes thus
(Because 24 degrees is the angle opposite side VW)
Multiply both sides by Sin24
(Approximated)
<em>At this stage, we have two known sides and two known angles;</em>
<em>The Area can be calculated as the 1/2 * the products of two sides * Sin of the angle between the two sides</em>
Considering VW and VU
VW = 23.5 (Calculated);
VU = 34 (Given)
The angle between these two sides is 120 (Calculated);
Hence;
<em>Hence, the area of the triangle is </em>