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Naddika [18.5K]
4 years ago
5

In Hooke’s law, what does the x represent?

Physics
2 answers:
Arte-miy333 [17]4 years ago
7 0
X Represents the distance the spring is stretched or compressed away from its equilibrium or rest position.
masha68 [24]4 years ago
6 0

Answer:

x is the displacement of spring

Explanation:

The Hooke's law gives the force acting on the spring when it is compressed or stretched. The mathematical expression for force is given by :

F=-kx

Where

k is the spring constant of and it shows the stiffness of spring.

x shows the displacement of spring when it is stretched or compressed from equilibrium position and it acts in opposite direction.

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List the main types of electromagnetic waves in order of increasing frequency. radio waves, microwaves, infrared, visible light,
alexandr1967 [171]

Answer:

radio waves, microwaves, infrared, visible light, ultraviolet light, X-rays, gamma rays

Explanation:

Electromagnetic waves are oscillations of electric and magnetic fields in a direction perpendicular to the direction of motion of the wave (transverse waves). They are classified into 7 different types, according to their frequencies.

From lowest to highest frequency, we have:

Radio waves

Microwaves 10^9 Hz - 4\cdot 10^{13}Hz

Infrared 4\cdot 10^{13} - 4\cdot 10^{14} Hz

Visible light 4\cdot 10^{14} - 8\cdot 10^{14}Hz

Ultraviolet 8\cdot 10^{14} - 2.4\cdot 10^{16} Hz

X-rays 2.4\cdot 10^{16} -5 \cdot 10^{19}Hz

Gamma rays >5\cdot 10^{19} Hz

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Explanation:

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How do we find the average force in physics?​
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3 years ago
Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.60 m away from the slits. (As
Naddik [55]

Answer:

a

   \lambda = 1.667 nm

b

     \theta  =  0.8681^o

Explanation:

From the question we are told that

   The distance of separation is d  =  0.220 \ mm  =  0.00022 \ m

    The  is distance of the screen from the slit is  D   =  2.60 \ m

    The distance between the central bright fringe and either of the adjacent bright   y  =  1.97 cm  =  1.97 *10^{-2}\ m

Generally  the condition for constructive interference is  

      d sin \tha(\theta ) =  n \lambda

From the question we are told that small-angle approximation is valid here.

So    sin (\theta ) = \theta

=>        d \theta  =  n \lambda

=>        \theta =  \frac{n *  \lambda }{d }

Here n is the order of maxima and the value is  n =  1 because we are considering the central bright fringe and either of the adjacent bright fringes

Generally the distance between the central bright fringe and either of the adjacent bright  is mathematically represented as

         y  =  D * sin (\theta )

From the question we are told that small-angle approximation is valid here.

So

       y  =  D * \theta

=>   \theta  =  \frac{ y}{D}

So

     \frac{n *  \lambda }{d } = \frac{y}{D}

     \lambda =\frac{d * y }{n * D}

substituting values

       \lambda =  \frac{0.00022 * 1.97*10^{-2} }{1 * 2.60 }

        \lambda = 1.667 *10^{-6}

        \lambda = 1.667 nm

In the b part of the question we are considering the next set of bright fringe so  n=  2

    Hence

     dsin (\theta ) =  n \lambda

    \theta  =  sin^{-1}[\frac{ n  *  \lambda }{d} ]

    \theta  =  sin^{-1}[\frac{ 2  *  1667 *10^{-9}}{ 0.00022} ]

    \theta  =  0.8681^o

7 0
4 years ago
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