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3 years ago

In Hooke’s law, what does the x represent?

Physics

2 answers:

Arte-miy333 [17]3 years ago

7 0

X Represents the distance the spring is stretched or compressed away from its equilibrium or rest position.

masha68 [24]3 years ago

6 0

Answer:

x is the displacement of spring

Explanation:

The Hooke's law gives the force acting on the spring when it is compressed or stretched. The mathematical expression for force is given by :

$F=-kx$

Where

k is the spring constant of and it shows the stiffness of spring.

x shows the displacement of spring when it is stretched or compressed from equilibrium position and it acts in opposite direction.

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How much heat is needed to raise the temperature of 50.0 g of water by 25.0°C

love history [14]

Answer:

Explanation:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

4.18

∘

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of

1 g

of that substance by

∘

In water's case, you need to provide

4.18 J

of heat per gram of water to increase its temperature by

∘

What if you wanted to increase the temperature of

1 g

of water by

∘

? You'd need to provide it with

increase by 1

∘



4.18 J

increase by 1

∘



4.18 J

increase by 2

∘



4.18 J

To increase the temperature of

1 g

of water by

∘

, you'd need to supply it with

increase by 1

∘



4.18 J

increase by 1

∘



4.18 J

...

increase by n

∘



4.18 J

Now let's say that you wanted to cause a

∘

increase in a

2-g

sample of water. You'd need to provide it with

for 1 g of water



4.18 J

for 1 g of water



4.18 J

for 2 g of water



4.18 J

To cause a

∘

increase in the temperature of

grams of water, you'd need to supply it with

for 1 g of water



4.18 J

for 1 g of water



4.18 J

,,,

for m g of water



4.18 J

This means that in order to increase the temperature of

grams of water by

∘

, you need to provide it with

heat

specific heat

This will account for increasing the temperature of the first gram of the sample by

∘

, of the the second gram by

∘

, of the third gram by

∘

, and so on until you reach

grams of water.

And there you have it. The equation that describes all this will thus be

⋅

, where

- heat absorbed

- the mass of the sample

- the specific heat of the substance

- the change in temperature, defined as final temperature minus initial temperature

In your case, you will have

100.0

⋅

4.18

∘

⋅

(

50.0

−

25.0

)

∘

10,450 J

Rounded to three sig figs and expressed in kilojoules, t

Explanation:

3 0

2 years ago

Read 2 more answers

In order to increase the amount of work done, we need to:

Nadusha1986 [10]

Option (D) is the correct one.

In order to increase the amount of work done, we need to increase the force applied to the object.

8 0

3 years ago

A 20 ft ladder leans against a wall. The bottom of the ladder is 3 ft from the wall at time t=0 and slides away from the wall at

stellarik [79]

Answer: 0.516 ft/s

Explanation:

Given

Length of ladder L=20 ft

The speed at which the ladder moving away is v=2 ft/s

after 1 sec, the ladder is 5 ft away from the wall

So, the other end of the ladder is at

$\Rightarrow y=\sqrt{20^2-5^2}=19.36\ ft$

Also, at any instant t

$\Rightarrow l^2=x^2+y^2$

differentiate w.r.t.

$\Rightarrow 0=2xv+2yv_y\\\\\Rightarrow v_y=-\dfrac{x}{y}\times v\\\\\Rightarrow v_y=-\dfrac{5}{19.36}\times 2=0.516\ ft/s$

5 0

2 years ago

A horizontal force of 140 N is needed to pull a 60kg box across the horizontal floor at constant speed . Find the coefficient of

____ [38]

Explanation:

formula for force is:

force=mass × acceleration

but in case of friction

force =coefficient of friction × Normal Reaction

F. = u × R

U = F/R

but when placed horizontally

R= M×G

M=mass=60kg

G=Gravity(10m/s or 9.8m/s)

F=140N

U=140/60×10

U=140/600

U=0.2333333333

approximately to 3 significant figures

U=0.233

if i am correct rate it 5 star

4 0

1 year ago

A horizontal object-spring system oscillates with an amplitude of 2.8 cm. If the spring constant is 275 N/m and object has a mas

Lisa [10]

Answer:

(a) the mechanical energy of the system, U = 0.1078 J

(b) the maximum speed of the object, Vmax = 0.657 m/s

Explanation:

Given;

Amplitude of the spring, A = 2.8 cm = 0.028 m

Spring constant, K = 275 N/m

Mass of object, m = 0.5 kg

(a) the mechanical energy of the system

This is the potential energy of the system, U = ¹/₂KA²

U = ¹/₂ (275)(0.028)²

U = 0.1078 J

(b) the maximum speed of the object

$V_{max} =\omega*A= \sqrt{\frac{K}{M} } *A\\\\V_{max} = \sqrt{\frac{275}{0.5} } *0.028\\\\V_{max} = 0.657 \ m/s$

$a_{max} = \frac{KA}{M} \\\\a_{max} = \frac{275*0.028}{0.5}\\\\a_{max} = 15.4 \ m/s^2$

6 0

2 years ago