Answer:
The maximum height to which water could be squirted with the hose is 13.380 meters.
Explanation:
A line of current of a fluid can be explained sufficiently by Bernoulli's Theorem. In this case, the system can be simplified due to neglectance of changes in absolute pressure. Water is squirted with an initial speed and reaches its maximum height, where final speed is zero. That is to say:
Where:
, - Initial and final height of water, measured in meters.
- Gravitational acceleration, measured in meters per square second.
, - Initial and final speed of water, measured in meters per second.
If , , and , then:
The maximum height to which water could be squirted with the hose is 13.380 meters.
Answer:
The average velocity of Samuel’s entire trip is 1.16 m/s.
Explanation:
Given:
Distance covered at first checkpoint (d₁) = 925 m
Distance covered at second checkpoint (d₂) = 673 m
Time taken for reaching first checkpoint (t₁) = 10 min = 10 × 60 = 600 s [∵1 min = 60 s]
Time taken for reaching second checkpoint (t₂) = 13 min = 13 × 60 = 780 s
Now, the average velocity of Samuel's entire trip is given by the formula:
Total distance traveled is equal to the sum of the distances traveled at first and second checkpoints. So,
Total distance covered =
Total time taken =
Therefore, the average velocity is given as:
Hence, the average velocity of Samuel’s entire trip is 1.16 m/s.
Answer:
5.234 m/s^2
Explanation:
Weight (force due to gravity) is proportional to the acceleration due to gravity. For some g' on MPAW, the relation is ...
g'/g = (2714 N)/(5185 N)
g' = g(2714/5185) = (10 m/s^2)(2714/5185)
g' ≈ 5.234 m/s^2
The new acceleration is
Explanation:
We can answer this problem by applying Newton's second law, which states that:
where
F is the net force on an object
m is the mass of the object
a is its acceleration
The equation can be rewritten as
In this problem, the initial acceleration is
Later:
- The net force is tripled:
- The mass is halved:
Therefore, the new acceleration is:
which means that the new acceleration is 6 times the original acceleration, therefore
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