Question

A certain heat engine does 30.2 kJ of work and dissipates 9.14 kJ of waste heat in a cyclical process.

Answer 1

Answer:

a) $H_{in}=39.34 kJ$

b) Efficiency=76.77%

Explanation:

a)

In order to solve this problem, we can use the following formula:

$H_{in}=H_{out}+W$

the problem provides us with all the necessary information so we can directly use the formula:

$H_{in}=9.14kJ+30.2kJ$

$H_{in}=39.34 kJ$

b) In order to find the efficiency, we can use the following formula:

$Efficiency=\frac{W}{H_{in}}*100\%$

so we get:

$Efficiency=\frac{30.2kJ}{39.34kJ}*100\%$

Efficiency=76.77%