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iogann1982 [59]
3 years ago
12

Can someone please tell me what this instrument is and how it works please? thanks! (◡‿◡ʃ♡ƪ)

Physics
2 answers:
Mrrafil [7]3 years ago
6 0

Answer:

refracting telescope.

Explanation:

it works by refracting light and showing the object through the lens.

hope this helps! <3

~mina

Lerok [7]3 years ago
3 0

Answer

Refracting telescope

Explanation:

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Answer: 0.0187 times the force between Sun and Earth.

The gravitational force between two massive bodies is directly proportional to their masses and inversely proportional to the square of distance between them.

F=G\frac {M_1M_2}{d^2}

where G is the gravitational constant.

Let,

The mass of the Sun be M_S

The mass of the Earth beM_E

The mass of the Neptune beM_N

The Distance between Sun and Earth be d_{SE}

The Distance between Sun and Neptune be d_{NE}

It is given that the mass of Neptune is 17 times mass of Earth.

\Rightarrow M_N=17M_E

The distance of Neptune from Sun is 30.1 times the distance of Earth from Sun.

\Rightarrow D_{SN}=30.1D_{SE}

The Force between Earth and Sun is F_{SE}=3.5\times10^{28}N

The Force between Neptune and Sun:

F_{SN}=G\frac{M_SM_N}{D_{SN}^2}=G\frac{M_S17M_E}{(30.1D_{SE})^2}=\frac {17}{30.1^2}G\frac{M_SM_E}{D_{SE}^2}=\frac {17}{30.1^2}F_{SE}=0.0187F_{SE}


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Velocity vs time graph
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Answer:

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We are able to see an object when it:
xenn [34]

Answer:

C. reflects one or more visible light frequencies.

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Compounds are created when atoms of different elements _____. form physical bonds have different chemical properties form chemic
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3 years ago
An unknown object is placed inside of a spherical container and dropped from an airplane. When empty, the spherical container ha
hichkok12 [17]

Answer:

The mass of unknown object is 8.62Kg

Explanation:

To develop this problem it is necessary to apply the equations related to the Drag force and the Force of Gravity.

For the given point, that is, the moment at which the terminal velocity is reached, the two forces equalize, that is,

F_D =F_g

By definition we know that the Drag force is defined as

F_D= \frac{1}{2} C_d \rho A V^2

Where,

C_d = Drag coefficient

\rho =Density

A =Cross-sectional Area

V = Velocity

In the other hand we have,

F_g = (m_1 +m_2) g

Where,

m_1 =Mass of sphere

m_2 =Mass of unknown object

Equating the two equations we have to

(m_1 +m_2) g=\frac{1}{2} C_d \rho A V^2

Re-arrange for m_2,

m_2 = \frac{1}{2g} C_d \rho A V^2 -m_1

Our values are given by,

C_d = 0.5

\rho = 1.22Kg/m^3

V = 66.7m/s

m_1 = 3Kg

d= 32.7*10^{-2}m

r = 16.35*10^{-2}m

Replacing in the equation we have,

m_2 = \frac{1}{2(9.8)}(0.5) (1.22) (\pi*(16.35*10^{-2})^2)*66.7^2 -3

m_2 = 8.62Kg

<em>Therefore the mass of unknown object is 8.62Kg</em>

4 0
3 years ago
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