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Leni [432]
2 years ago
5

Two unknown household items are being tested with litmus paper. Substance A turns red litmus paper blue and Substance B turns bl

ue litmus paper red. Which of the following best explains the results of the experiment?
Both Substances A and B are bases.

Substance A is an acid and Substance B is a base.

Both Substances A and B are acids.

Substance A is a base and Substance B is an acid.
Chemistry
1 answer:
irina1246 [14]2 years ago
7 0

Answer:

Substance A is a base and Substance B is an acid.

According to the experimental results

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The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

Ea = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
A solution contains 0.036 M Cu2+ and 0.044 M Fe2+. A solution containing sulfide ions is added to selectively precipitate one of
Ratling [72]

Answer:

The precipitate is CuS.

Sulfide will precipitate at  [S2-]= 3.61*10^-35 M

Explanation:

<u>Step 1: </u>Data given

The solution contains 0.036 M Cu2+ and 0.044 M Fe2+

Ksp (CuS) = 1.3 × 10-36

Ksp (FeS) = 6.3 × 10-18

Step 2:  Calculate precipitate

CuS → Cu^2+ + S^2-         Ksp= 1.3*10^-36

FeS → Fe^2+ + S^2-      Ksp= 6.3*10^-18

Calculate the minimum of amount needed to form precipitates:

Q=Ksp

<u>For copper</u>  we have:  Ksp=[Cu2+]*[S2-]

Ksp (CuS) = 1.3*10^-36 = 0.036M *[S2-]

[S2-]= 3.61*10^-35 M

<u>For Iron</u>  we have: Ksp=[Fe2+]*[S2-]

Ksp(FeS) = 6.3*10^-18 = 0.044M*[S2-]

[S2-]= 1.43*10^-16 M

CuS will form precipitates before FeS., because only 3.61*10^-35 M Sulfur Ions are needed for CuS. For FeS we need 1.43*10^-16 M Sulfur Ions which is much larger.

The precipitate is CuS.

Sulfide will precipitate at  [S2-]= 3.61*10^-35 M

3 0
3 years ago
The reaction between sulfur dioxide and oxygen is reversible.
RUDIKE [14]

Explanation:

the correct answer is

D) 0.636 mol/dm³

3 0
2 years ago
What is the solvent in blood?
sergeinik [125]

Answer:

Water serves to suspend the red blood cells to carry oxygen to the cells. It is the solvent for the electrolytes and nutrients needed by the cells, and also the solvent to carry waste material away from the cells. With water as the solvent, osmotic pressure acts to transport the needed water into cells.

Explanation:

4 0
3 years ago
What are physical properties of Cobalt Silicate ?
seraphim [82]

Answer:

Some of the properties of cobalt silicate include:

It occurs as a crystal with red- violet type colour.

The shape of the cobalt silicate crystal is orthorhombic.

The molecular weight of cobalt silicate is 209.95.

The melting temperature of Cobalt Silicate is 1618 degrees Celsius.

The density of Cobalt Silicate is 4.63 grams per centimetre cube.

Cobalt Silicate can serve as a semi-conductor.

8 0
2 years ago
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