The answer is False. Hope this helps!!!
Answer:
I suppose that oxygen bonds with the carbon and escape the molten metal in a gaseous form. Not sure about this but i tried to help.
Explanation:
Answer:
ΔH = -110.5kJ
Explanation:
It is possible to obtain enthalpy of combustion of a particular reaction by the algebraic sum of similar reactions (Hess's law). Using:
1. C(s) + O₂(g) → CO₂(g) ΔH₁ = -393.5kJ
2. CO(g) + 1/2O₂(g) → CO₂(g) ΔH₂ = -283.0kJ
The sum of 1 -2 gives:
C(s) + <u>O₂(g)</u> + <u>CO₂(g)</u> → <u>CO₂(g)</u> + CO(g) + <u>1/2O₂(g)</u>
C(s) + 1/2O₂(g) → CO(g) ΔH = -393.5kJ - (-283.0kJ) =
<h3>ΔH = -110.5kJ</h3>
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The standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ is to be determined. We are given their reduction potentials:
-0.19 v for A
-0.85 v for B
To solve for the standard cell potential, examine the reaction and
the standard cell potential for this case is (-0.19- (-0.85)) v = -0.66 v<span />
