The loaded cab of an elevator has a mass of 3.0 x 10 3 kg and moves 200 m up the shaft in 20 s at constant speed. At what averag
1 answer:
The average rate at which the cable does work is 294,000 J/s.
The given parameters:
- <em>mass, m = 3000 kg</em>
- <em>height, h = 200 m</em>
- <em>time of motion, t = 20 s</em>
The average rate at which the cable does work is calculated as follows;
Thus, the average rate at which the cable does work is 294,000 J/s.
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Answer:
The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²
The shear stress at a distance 0.5-in away from the pipe wall is 0
Explanation:
Given;
pressure drop per unit length of pipe = 0.6 psi/ft
length of the pipe = 12 feet
diameter of the pipe = 1 -in
Pressure drop per unit length in a circular pipe is given as;
make shear stress (τ) the subject of the formula
Where;
τ is the shear stress on the pipe wall.
ΔP is the pressure drop
L is the length of the pipe
r is the distance from the pipe wall
Part (a) shear stress at a distance of 0.3-in away from the pipe wall
Radius of the pipe = 0.5 -in
r = 0.5 - 0.3 = 0.2-in = 0.0167 ft
ΔP = 0.6 psi/ft
ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²
Part (b) shear stress at a distance of 0.5-in away from the pipe wall
r = 0.5 - 0.5 = 0
Instantaneous center:
It is the center about a body moves in planer motion. The velocity of Instantaneous center is zero and Instantaneous center can be lie out side or inside the body. About this center every particle of a body rotates.
From the diagram
Where these two lines will cut then it will the I-Center.Point A and B is moving perpendicular to the point I.
If we take three link link1,link2 and link3 then I center of these three link will be in one straight line It means that they will be co-linear.
Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.
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