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77julia77 [94]
3 years ago
5

On which factors does friction depend ?​

Physics
1 answer:
goldenfox [79]3 years ago
3 0

Answer:

It depends on 2 factors

the nature of the materials

the normal force.

Explanation:

It depends on 2 factors

the nature of the materials that are in friction and the treatment that they have followed. This factor is expressed by a numerical value called the coefficient of friction or friction.

the force exerted by one body on the other, that is, the normal force.

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in general, what happens to the energy, order, and spacing of particles when a solid turns to a liquid?
vodka [1.7K]
For a solid to change its state of matter into  liquid, energy is applied or heat is being used. With a solid, particles are very compacted and still, with a liquid they are not as compacted but can still take a defined shape.
 
6 0
3 years ago
Select the correct answer.
Triss [41]

Answer:

Jim's kinetic energy is 54.67 J.

Explanation:

Given that,

Mass, m = 15 kg

Velocity, V = 2.7 m/s

We need to find the Jim's kinetic energy. We know that when the object is in motion, it has kinetic energy. This energy is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 15\ kg\times (2.7\ m/s)^2

E = 54.67 J

So, Jim's kinetic energy is 54.67 J. Hence, this is the required solution.

5 0
3 years ago
A 40 foot beam that weighs 125 pounds is supported at the two ends by walls. It also supports a 600 pound AC unit 5 feet from th
Dmitrij [34]

Answer:

A) 588 pounds

Explanation:

According to the given conditions, we assume the beam to be simply supported at the ends carrying a uniformly distributed load of 125 pounds per feet and a point load of 600 pounds acting at 5 feet from the right support.

Referring the schematic:

<u>Moment about any point will be zero in equilibrium condition. </u>

∴Take moment about point L

F_r\times 40=125\times 20+35\times 600

F_r=587.5 lb

8 0
4 years ago
Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d
KIM [24]

Answer:

a)Car E = Car D  > (Car F = Car B = Car C) > Car A

b)Car E = Car D  > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

Car E:mass = 4000 kg; speed = 5 m/s

Car F: mass = 1000 kg; speed = 10 m/s

Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

<em>CarA:</em>

P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s

<em>Car B:</em>

P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s

Car C:

P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s

Car D:

P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s

Car E:

P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s

Car F:

P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s

So the momentum is given as ,

Car E = Car D  > (Car F = Car B = Car C) > Car A

Part b)Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Car E = Car D  > (Car F = Car B = Car C) > Car A

3 0
3 years ago
At what phase or phases could water exist at 4.579mm pressure and 0.0098°C?
zimovet [89]
The correct answer is A. The water at this conditions is in the solid phase. This can be verified by using a phase diagram. A phase diagram is a figure which shows the phases of a certain substance at a specific temperature and pressure.
7 0
4 years ago
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