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Tom [10]
3 years ago
9

Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height

of 30.0 m. During the collision at the bottom of the elevator shaft, a 86.0 kg passenger is stopped in 5.00 ms. (Assume that neither the passenger nor the cab rebounds.) What are the magnitudes of the (a) impulse and (b) average force on the passenger during the collision

Physics
1 answer:
Elena L [17]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

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Two uncharged metal spheres, #1 and #2, are mounted on insulating support rods. A third metal sphere, carrying a positive charge
tatuchka [14]

Answer:

The question is incomplete as some details are missing, here is the details ;

In this final state

a) spheres #1 and #2 both carry negative charge.

b) sphere #1 carries negative charge and #2 carries positive charge.

c) spheres #1 and #2 are still uncharged.

d) sphere #1 carries positive charge and #2 carries negative charge.

e) spheres #1 and #2 both carry positive charge.

Explanation:

From the concept of electrostatics, if a positively charged sphere is brought close to #2, there will be attraction of the opposite charges(-ve) towards it.

Now connecting a copper wire between #1 and #2, opposite charges will flow from #1 towards #2. disconnecting the copper wire makes #1 to be positively charged and #2 to be negatively charge and from the laws of attraction ; Like charges repel and unlike charges attract. the correct option is d.

5 0
3 years ago
If velocity is positive, which woul
shusha [124]

Answer:

C. An inital volocity that is faster than the final volocity

Explanation:

.

5 0
3 years ago
If a train is travelling 200km/hour eastward for 1800 seconds how far does it travel?
Olenka [21]

Answer:

Distance, d = 99990 meters

Explanation:

It is given that,

Speed of the train, v = 200 km/h = 55.55 m/s

Time taken, t = 1800 s

Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :

v=\dfrac{d}{t}

d=v\times t

d=55.55\times 1800

d = 99990 m

So, the distance covered by the train is 99990 meters. Hence, this is the required solution.

5 0
3 years ago
In the desert air, sound travels at 358 meters per second (m/s). In the polar air, sound travels at 330 meters per
Sati [7]

Answer:

The correct option is;

C. The temperature of the air affects the speed of sound

Explanation:

The information given are;

The speed with which sound travels in the desert air = 358 m/s

The speed with which sound travels in the polar air = 330 m/s

The major difference between the desert air and the polar air is that the temperature of the desert air is hotter than the temperature of the air in the polar region. Therefore the speed of sound is affected by the air temperature.

The equation that gives the relationship of the speed of sound in air, v_{air}, to temperature is presented as follows;

v_{air} = 331\frac{m}{s} \times \sqrt{\dfrac{T_K}{273 K} } =  331\frac{m}{s} \times \sqrt{1 + \dfrac{T_{^{\circ}C}}{273 ^{\circ} C} }

Which shows that the speed of sound in air, v_{air}, rises as the temperature of the air rises.

Where;

T_{^{\circ}C} = The temperature of the air in degrees Celsius

T_K = The temperature of the air in degrees Kelvin.

7 0
3 years ago
According to the work equation, if you want to increase the distance on the
natka813 [3]
I think the answer is B because I did this before
7 0
3 years ago
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