Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
of 30.0 m. During the collision at the bottom of the elevator shaft, a 86.0 kg passenger is stopped in 5.00 ms. (Assume that neither the passenger nor the cab rebounds.) What are the magnitudes of the (a) impulse and (b) average force on the passenger during the collision
1 answer:
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Answer:
7.05 Volts/m
Explanation:
L = length of the Nichrome wire = 44 cm = 0.44 m
V = Potential difference across the end of the wire = battery voltage = 3.1 Volts
E = magnitude of electric field inside the wire
Magnitude of electric field inside the wire is given as
Inserting the values
E = 7.05 Volts/m
Answer:
0.14c
0.003 s
Explanation:
See attachment
