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shutvik [7]
3 years ago
14

What is the ph of a solution that is 0.06 m in sodium benzoate (nac7h5o2) and 0.09 m in benzoic acid (hc7h5o2)?

Chemistry
1 answer:
Alchen [17]3 years ago
6 0

To determine the pH of a solution which has 0.06 m in sodium benzoate (nac7h5o2) and 0.09 m in benzoic acid (hc7h5o2), we use the ICE table and the acid dissociation constant of hc7h5o2 to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:

<span>
HC7H5O2 = H+ + C7H5O2-
</span>NaC7H5O2 = Na+ + C7H5O2<span>-

Therefore, the only source of hydrogen ion would be the acid. We use the ICE table,
                   </span>HC7H5O2           H+        C7H5O2<span>-
I                     0.09                  0              0.06
C                      -x                    +x               +x
------------------------------------------------------------------
E                 0.09-x                x              0.06+ x

Ka = </span>6.28x10^(-5)<span> = (0.06 + x) (x) / 0.09 -x 
x = 9.40x10^-5 M = [H+]

pH = - log [H+] 
pH = -log </span> 9.40x10^-5 M<span>
pH = 4.03<span>

Therefore, the pH of the resulting solution would be 4.03.</span></span>

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