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shutvik [7]
3 years ago
14

What is the ph of a solution that is 0.06 m in sodium benzoate (nac7h5o2) and 0.09 m in benzoic acid (hc7h5o2)?

Chemistry
1 answer:
Alchen [17]3 years ago
6 0

To determine the pH of a solution which has 0.06 m in sodium benzoate (nac7h5o2) and 0.09 m in benzoic acid (hc7h5o2), we use the ICE table and the acid dissociation constant of hc7h5o2 to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:

<span>
HC7H5O2 = H+ + C7H5O2-
</span>NaC7H5O2 = Na+ + C7H5O2<span>-

Therefore, the only source of hydrogen ion would be the acid. We use the ICE table,
                   </span>HC7H5O2           H+        C7H5O2<span>-
I                     0.09                  0              0.06
C                      -x                    +x               +x
------------------------------------------------------------------
E                 0.09-x                x              0.06+ x

Ka = </span>6.28x10^(-5)<span> = (0.06 + x) (x) / 0.09 -x 
x = 9.40x10^-5 M = [H+]

pH = - log [H+] 
pH = -log </span> 9.40x10^-5 M<span>
pH = 4.03<span>

Therefore, the pH of the resulting solution would be 4.03.</span></span>

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A buffer solution contains an equivalent amount of acid and base. The pH of the solution with an acid dissociation constant (pKa) value of 3.75 is 3.82.

<h3>What is pH?</h3>

The amount of hydrogen or the proton ion in the solution is expressed by the pH. It is given by the sum of pKa and the log of the concentration of acid and bases.

Given,

Concentration of salt [HCOO⁻] = 0.24 M

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The acid dissociation constant (pKa) = 3.75

pH is calculated from the Hendersons equation as,

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= 3.82

Therefore, 3.82 is the pH of the buffer.

Learn more about pH here:

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