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3 years ago

The empirical formula is:

Chemistry

1 answer:

Hunter-Best [27]3 years ago

5 0

Answer:

C. the relative number of atoms of each element, using the lowest whole ratio.

Explanation:

The empirical formula is how we simplify the whole formula to simplify it to its smallest indivisible parts.

It is definitely not the actual number of atoms. If you see an empirical formula, don't think that it's the full thing.

It is also not a representation of a compound to show its atoms' arrangement: this would be a Lewis dot structure, or a ball and stick model, or something similar. We don't use the empirical formula for this purpose.

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An element consists of 1.40% of an isotope

Dmitriy789 [7]

Answer:

I think it's lead (pb). Hope this helps.

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3 years ago

Read 2 more answers

The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal: CO(g) + H2O(g)

taurus [48]

<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

<u>Explanation:</u>

For the given chemical reaction:

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

The expression of $K_c$ for above reaction follows:

$K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}$ ........(1)

We are given:

$[CO]_{eq}=[H_2O]_{eq}=[H_2]_{eq}=0.10M$

$[CO_2]_{eq}=0.40M$

Putting values in above equation, we get:

$K_c=\frac{0.40\times 0.10}{010\times 0.10}\\\\K_c=4$

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of hydrogen gas = 0.30 mol

Volume of solution = 2.0 L

Putting values in above equation, we get:

$\text{Molarity of }H_2=\frac{0.30mol}{2L}=0.15M$

When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.

Concentration of hydrogen gas when equilibrium is re-established = 0.1 + 0.15 = 0.25 M

Now, the equilibrium is shifting to the reactant side. The equation follows:

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Initial: 0.1 0.1 0.4 0.1

At eqllm: 0.1+x 0.1+x 0.4-x 0.25-x

Putting values in expression 1, we get:

$4=\frac{(0.25-x)(0.4-x)}{(0.1+x)(0.1+x)}\\\\3x^2+1.45x-0.06=0\\\\x=0.038,-0.522$

Neglecting the negative value of 'x'

Calculating the concentrations of the species:

Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M

Concentration of hydrogen gas = (0.25 - x) = (0.25 - 0.038) = 0.212 M

Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Concentration of water = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Hence, the concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

8 0

4 years ago

Where glucose is broken down into smaller molecules to produce energy. The second part of the process takes place in the

slavikrds [6]

Answer:

Mitochondria

Explanation:

Glucose in an energy molecule contained in carbohydrate food substances. The end product of the digestion of carbohydrate is glucose which is broken down to produce energy.

The sequence of breakdown of glucose is as follows; In the first step, 6-carbon glucose is broken down into two molecules of 3-carbon pyruvic acid. This occurs in the cytoplasm of the cell. It is an anaerobic process.

In the second step which occurs in the mitochondrion, each of the molecules of pyruvic acid is now oxidized to carbon dioxide and water and energy is produced in the process.

5 0

3 years ago

QUICK PLEASE HELP!!!during a combustion reaction, 5.00 grams of oxygen reacted with 5.00 grams of CH4.

stealth61 [152]

The balanced chemical reaction is:

CH4 + 2O2 —> CO2 + 2H2O

You need to convert mass to moles (divide by molar mass):

CH4 moles = 5 / 16 = 0.31 mol
O2 moles = 5 / 32 = 0.16 mol

To figure out which reactant is limiting, divide the actual moles by the corresponding coefficient in the reaction:

CH4: 0.31 / 1 = 0.31
O2: 0.16 / 2 = 0.08

O2 is the lower number, so it is the limiting reactant. From the reaction we know it takes 2 moles of O2 to react with each mole of CH4. Therefore, for however many moles of O2 we actually have, half as many moles of CH4 will react. Since we have 0.16 mol of O2, only 0.08 mol of CH4 will react, leaving behind 0.31 - 0.08 = 0.23 mol of CH4.

Now convert back to mass (multiply by molar mass) to find the mass of CH4 remaining:

0.23 x 16 = 3.68g

The closest answer is B.

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3 years ago

A pure substance is found to have an empirical formula of CH and a molar mass of 78.114 grams. What is the molecular formula of

harkovskaia [24]

Answer:

Explanation:

Skamn jeksk

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3 years ago