What is acceleration of a body moving with uniform velocity? (convert 50km/hr into m/s)

Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa

anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are $146.03\times10^{3}\ N/C$ and 75.36°.

Explanation:

Given that,

First charge $q_{1}= 2.9\mu C$

Second charge $q_{2}= 2.9\mu C$

Distance between two corners r= 50 cm

We need to calculate the electric field due to other charges at one corner

For E₁

Using formula of electric field

$E_{1}=\dfrac{kq}{r'^2}$

Put the value into the formula

$E_{1}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\sqrt{2}\times10^{-2})^2}$

$E_{1}=52200=52.2\times10^{3}\ N/C$

For E₂,

Using formula of electric field

$E_{1}=\dfrac{kq}{r^2}$

Put the value into the formula

$E_{2}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\times10^{-2})^2}$

$E_{2}=104400=104.4\times10^{3}\ N/C$

We need to calculate the horizontal electric field

$E_{x}=E_{1}\cos\theta$

$E_{x}=52.2\times10^{3}\times\cos45$

$E_{x}=36910.97=36.9\times10^{3}\ N/C$

We need to calculate the vertical electric field

$E_{y}=E_{2}+E_{1}\sin\theta$

$E_{y}=104.4\times10^{3}+52.2\times10^{3}\sin45$

$E_{y}=141310.97=141.3\times10^{3}\ N/C$

We need to calculate the net electric field

$E_{net}=\sqrt{E_{x}^2+E_{y}^2}$

Put the value into the formula

$E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}$

$E_{net}=146038.69\ N/C$

$E_{net}=146.03\times10^{3}\ N/C$

We need to calculate the direction of electric field

Using formula of direction

$\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}$

$\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})$

$\theta=75.36^{\circ}$

Hence, The magnitude of the electric field and direction of electric field are $146.03\times10^{3}\ N/C$ and 75.36°.

4 0

2 years ago

Eq-45 what type of boat requires navigation lights?

irina [24]

All the boats operating at night requires Navigation light.

Navigation light helps prevent collisions between boats and see if visibility is poor. The types of boat are : Rowboats, Tug boats, Vessels, Sailboat etc.

Various boats have different lightning color to show its use and side of the boat.

8 0

3 years ago

A simple series circuit consists of a 150 Ω resistor, a 29 V battery, a switch, and a 2.1 pF parallel-plate capacitor (initially

Rufina [12.5K]

Find the electric flux and the disp at t=0.50ns
Given: 
Resistor R = 160 Ω 
Voltage ε = 22.0 V 
Capacitor C = 3.10 pF = 3.10 * 10^-12 F 
time t = 0.5 ns = 0.5 * 10^-9 s 
ε0 = 8.85 * 10^-12 
Solution: 
ELECTRIC FLUX: 
Φ = Q/ε0 
we have ε0, we need to find Q the charge 
STEP 1: FIND Q 
Q = C ε ( 1 - e^(-t/RC) ) 
Q = { 3.10 * 10^-12 } { 22.0 } { 1 - e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } 
Q = { 3.10 * 10^-12 } { 22.0 } { 1 - 0.365 } 
Q = { 3.10 * 10^-12 } { 22.0 } { 0.635 } 
Q = 43.31 * 10^-12 C 
STEP 2: WE HAVE Q AND ε0 > >>> SOLVE FOR ELECTRIC FLUX >>> 
Φ = Q/ε0 
Φ = { 43.31 * 10^-12 C } / { ε0 = 8.85 * 10^-12 } 
Φ = 4.8937 = 4.9 V.m 
DISPLACEMENT CURRENT 
we use the following equation: 
I = { ε / R } { e^(-t/RC) } 
I = { 22 / 160 } { e^(- 0.5 * 10^-9 / 160 *3.10 * 10^-12 ) } 
I = { 0.1375 } { 0.365 } 
I = 0.0502 A = 0.05 A

8 0

3 years ago

What is velocity change divided by time change?

Luda [366]

Acceleration: is the change in velocity divided by the time it takes for the change to occur. . Acceleration is the change in verity divided by the time it takes to make the change, Acceleration has direction.

5 0

3 years ago

compare to visible light, the wavelength of x-rays is shorter longer or the same and the frequency is lower higher or the same

Doss [256]

Answer:shorter higher

Explanation:Compare to visible light, the wavelength of X-rays is shorter and then frequency is higher

7 0

2 years ago

What is acceleration of a body moving with uniform velocity? (convert 50km/hr into m/s)​

What is acceleration of a body moving with uniform velocity? (convert 50km/hr into m/s)