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Doss [256]
3 years ago
6

A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never inclu

de units in the answer to a numerical question.)
Physics
1 answer:
inysia [295]3 years ago
4 0
For Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
F=ma
Rewriting the acceleration as the increment of velocity \Delta v in a time \Delta t: a= \frac{\Delta v}{\Delta t}, F becomes
F=m \frac{\Delta v}{\Delta t}
But given the definition of momentum: p=mv, then m \Delta v represents the momentum change. So we can rewrite F as
F= \frac{\Delta p}{\Delta t}
And re-arranging the formula we can calculate the value of the change in momentum:
\Delta p = F \Delta t=(8.0 N)(0.50 s)=4 kg m/s
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While passing a slower car on the highway, you accelerate uniformly from 20.1 m/s to 33.2 m/s in a time of 10.6 s. How far do yo
BaLLatris [955]

Answer:

282 m

Explanation:

Given:

v₀ = 20.1 m/s

v = 33.2 m/s

t = 10.6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (33.2 m/s + 20.1 m/s) (10.6 s)

Δx ≈ 282 m

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What is the period? Blank seconds.
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If sunlight begins to warm a frozen lake, the atoms in the lakes frozen water will begin to move faster. True of False?
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3 years ago
Calculate, for the judge, how fast you were going in miles per hour when you ran the red light because it appeared Doppler-shift
sammy [17]

Answer:

The doppler effect equation is:

f' = \frac{v +v0}{v - vs}*f

In the equation we have frequencies, but then we have the wavelengths of the lights, remember the relation:

v = f*λ

then:

f = v/λ

and v is the speed of light, then:

f = c/λ

where:

f' is the observed frequency, in this case, is equal to f = (3*10^17nm/s)/550 nm

f is the real frequency, in this case, is (3*10^17nm/s)/650 nm

vs is the speed of the source, in this case, the source is not moving, then vs = 0 m/s.

v is the speed of the wave, in this case, is equal to the speed of light, v = 3*10^8 m/s

v0 is your speed, this is what we want to find.

Replacing those quantities in the equation, we get:

(3*10^17nm/s)/550 = (3*10^8 m/s + v0)/(3*10^8 m/s)*(3*10^17nm/s)/650 nm

(650nm)/(550nm) = (3*10^8 m/s + v0)/(3*10^8 m/s)

1.182*(3*10^8 m/s) = (3*10^8 m/s + v0)

1.182*(3*10^8 m/s) -  (3*10^8 m/s) = v0 = 54,600,000 m/s

So your speed was 54,600,000 m/s, which is a lot.

6 0
3 years ago
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