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Doss [256]
3 years ago
6

A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never inclu

de units in the answer to a numerical question.)
Physics
1 answer:
inysia [295]3 years ago
4 0
For Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
F=ma
Rewriting the acceleration as the increment of velocity \Delta v in a time \Delta t: a= \frac{\Delta v}{\Delta t}, F becomes
F=m \frac{\Delta v}{\Delta t}
But given the definition of momentum: p=mv, then m \Delta v represents the momentum change. So we can rewrite F as
F= \frac{\Delta p}{\Delta t}
And re-arranging the formula we can calculate the value of the change in momentum:
\Delta p = F \Delta t=(8.0 N)(0.50 s)=4 kg m/s
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What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
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The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

<h3>What is a frequency?</h3>

The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.

Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,

\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma  = 6.88 \times 10^{14}\ s^{-1}

Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

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2 years ago
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The number of employees for a certain company has been decreasing each year by 4%. If the company currently has 650 employees an
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8 0
3 years ago
Which of the following is most useful to determine how much energy is being used by a circuit in a given amount of time?
user100 [1]

Answer:

The answer is A.

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Two objects are electrically charged. The net charge on one object is doubled. Therefore, the electric force _____.
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7 0
3 years ago
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Find the rms speed of the molecules of a sample of n2 (diatomic nitrogen) gas at a temperature of 31.5°c.
Artemon [7]
The rms speed can be calculated using the following rule:
rms = sqrt ((3RT) / (M)) where:
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Substitute with the givens to get the rms speed as follows:
rms speed = sqrt [(3*8.314*304.5) / (0.028)] = 520.811 m/sec
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3 years ago
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