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Doss [256]
3 years ago
6

A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never inclu

de units in the answer to a numerical question.)
Physics
1 answer:
inysia [295]3 years ago
4 0
For Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
F=ma
Rewriting the acceleration as the increment of velocity \Delta v in a time \Delta t: a= \frac{\Delta v}{\Delta t}, F becomes
F=m \frac{\Delta v}{\Delta t}
But given the definition of momentum: p=mv, then m \Delta v represents the momentum change. So we can rewrite F as
F= \frac{\Delta p}{\Delta t}
And re-arranging the formula we can calculate the value of the change in momentum:
\Delta p = F \Delta t=(8.0 N)(0.50 s)=4 kg m/s
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4) Write down the transformation of energy in torch light.<br>​
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Answer:

<u>The transformation of energy in a torch light is as follows:</u>

1) When the torch is turned ON, the chemical energy in the batteries is converted into electrical energy.

2) The electrical energy is converted into heat and light energy. (We feel the torch to be hot after some time and we can see the light energy)

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
3 years ago
Which type of energy is released when a bond between atoms is broken
scoray [572]

Answer:

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Explanation:

7 0
3 years ago
An insulated beaker with negligible mass contains 0.250 kg of water at 75.0C. How many kilograms of ice at -20.0C must be droppe
kkurt [141]

Answer:

The amount of kilograms of ice at -20.0°C that must be dropped into the water to make the final temperature of the system 40.0°C = 0.0674 kg

Explanation:

Heat gained by ice in taking the total temperature to 40°C = Heat lost by the water

Total Heat gained by ice = Heat used by ice to move from -20°C to 0°C + Heat used to melt at 0°C + Heat used to reach 40°C from 0°C

To do this, we require the specific heat capacity of ice, latent heat of ice and the specific heat capacity of water. All will be obtained from literature.

Specific heat capacity of ice = Cᵢ = 2108 J/kg.°C

Latent heat of ice = L = 334000 J/kg

Specific heat capacity of water = C = 4186 J/kg.°C

Heat gained by ice in taking the total temperature to 40°C = mCᵢ ΔT + mL + mC ΔT = m(2108)(0 - (-20)) + m(334000) + m(4186)(40 - 0) = 42160m + 334000m + 167440m = 543600 m

Heat lost by water = mC ΔT = 0.25 (4186)(75 - 40) = 36627.5 J

543600 m = 36627.5

m = 0.0674 kg = 67.4 g of ice.

3 0
3 years ago
The gravitational force between the charged constituents of the atom is negligible compared with the electric force between them
katrin2010 [14]

Answer: The initial force is reduced a factor 1/4 when the separation between charge is doubled

Explanation: As it well known the electric force between two charges is given by:

Finitial=k*q1*q2/d^2 where d is the distance between charges and k is a constant

if the distance is doubled this means 2*dinitial thus the new force is equal to F initial* 1/4

6 0
3 years ago
!!please help !!!!! I’ll give brainliest
Oxana [17]
The answer is 45 degrees
7 0
3 years ago
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