Answer: - 7500N
Explanation:
Given the following :
Initial Velocity of car = 108km/hr
Time taken to stop after applying brakes = 4s
Mass of passengers in car = 1000kg
Force exerted by the brakes on the car =?
After 4s, then final Velocity (V) = 0
Initial Velocity (u) of the car = 108km/hr
108km/hr = (108 × 1000)m ÷ (3600)s = 30m/s
Force exerted = mass(m) × acceleration(a)
Acceleration of car = Change in Velocity with time
a = (v - u) / t
a = (0 - 30) / 4
a = - 30/ 4
a = - 7.5m/s^2
Therefore,
Force exerted = mass(m) × acceleration(a)
Force exerted = 1000kg × (-7.5)m/s^2
Force exerted = - 7500N
Answer:
The speed of the car at the end of the 2nd second = 8.0 m/s
Explanation:
The equations of motion will be used to solve this problem.
A car starts from rest,
u = initial velocity of the car = 0 m/s
Accelerates at a constant rate in a straight line,
a = constant acceleration of the car = ?
In the first second the car moves a distance of 2.0 meters,
t = 1.0 s
x = distance covered = 2.0 m
x = ut + (1/2)at²
2 = 0 + (1/2)(a)(1²)
a = 4.0 m/s²
How fast will the car be moving at the end of the second second
Now,
a = 4.0 m/s²
u = initial velocity of the car at 0 seconds = 0 m/s
v = final velocity of the car at the end of the 2nd second = ?
t = 2.0 s
v = u + at
v = 0 + (4×2)
v = 8.0 m/s
According to the theory, energy realized during the reaction is captured by the energy-carrying molecule ATP (adenosine triphosphate). Cellular respiration is the process by which organism use oxygen to break down food molecule to get chemical energy for cell function
C) volume and temperature.
Answer:
<h2>4</h2>
Explanation:
Mechanical advantage is defined as the ratio of the load to the effort applied to raise the load. If minimal effort is used to overcome a much larger load, that is when we have what is called mechanical advantage i.e a machine has been used to our advantage.
Mathematically, MA = Load/Effort
Given parameters
Load = 160N
Effort = 40N
Required
Mechanical Advantage
Using the formula above
MA = 160N/40N
MA = 4
<em>advantage</em>