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The molarity and normality of 5.7 g of Ca(OH)2 in 450ml 0f solution is calculated as follows
molarity = moles/volume in liters
moles =mass/molar mass
= 5.7g/74g/mol = 0.077moles
molarity = 0.077/450 x1000= 0.17M
Normality = equivalent point x molarity
equivalent point of Ca(OH)2 is 2 since it has two Hydrogen atom
normality is therefore = 0.17 x2 = 0.34 N
Answer:
81.5 L
Explanation:
We can use the combined gas law equation that gives the relationship among pressure, temperature and volume of gases for a fixed amount of gas.
P1V1 / T1 = P2V2 / T2
where P1 - pressure, V1 - volume and T1 - temperature at the first instance
P2 - pressure, V2 - volume and T2 - temperature at the second instance
substituting the values in the equation
1240 Torr x 47.2 L / 298 K = 730 Torr x V2 / 303 K
V2 = 81.5 L
the new volume the gas would occupy when the conditions have changed is 81.5 L
For Row 1 according to the respective Column is
- Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+
For Row 2 according to the respective Column is
- Mn, 25, 55, 25, 25,30, 3-
For Row 3 according to the respective Column is
For Row 4 according to the respective Column is
- O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-
For Row 5 according to the respective Column is
- Na, 11, 23, 11, 10, 12, 1-
From the question we are told
Ions, isotope, average atomic mass fill in the blank
Generally
Where
- Z signifies the Proton Number of the atom
- A signifies Mass Number of the atom
Therefore
For Row 1 according to the respective Column is
- Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+
For Row 2 according to the respective Column is
- Mn, 25, 55, 25, 25,30, 3-
For Row 3 according to the respective Column is
For Row 4 according to the respective Column is
- O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-
For Row 5 according to the respective Column is
- Na, 11, 23, 11, 10, 12, 1-
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