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Amiraneli [1.4K]
3 years ago
9

A hypothesis is tested by ___.

Chemistry
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer:

A.

Explanation:

because a theory is like a prediction and a prediction is like a hypothesis.

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What are the Group 1A and Group 7A elements examples of?
Scrat [10]
Alkali metals = Group 1A
Halogens = Group 7A
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4 years ago
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Find the pH of a solution whose hydronium concentration is 1.0 x 10-11​
Alborosie

Answer:

11

Explanation:

pH=-log(H+)

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4 years ago
The P:OP:O ratio is the amount of inorganic phosphate incorporated into ATP per atom of oxygen consumed. It represents the coupl
Ray Of Light [21]

Answer:

For NADH; P:O = 2.5

For FADH ₂; P : O = 1.5

Explanation:

The P:O (phosphate:oxygen) ratio represents the amount of inorganic phosphate, Pi used per atom of oxygen consume to synthesize ATP.

The Chemiosmotic theory predicts H⁺:O and H⁺:ATP ratios. Experimentally these appear to be 10 and 4 respectively when NADH is the substrate, equivalent to a P:O ratio of 2.5, and 6 and 4 respectively for FAD-linked substrates (e.g. succinate), equivalent to a P:O ratio of 1.5.

1. Electron flow from NADH to O₂ pumps protons at three sites to yield 3 ATP (P:O = 2.5)

For NADH: 10 H ⁺ translocated/O (2e -)

ATP/2e - = (10 H⁺/ 4 H +) = 2.5  

2. Succinate (via FADH2) bypasses site 1 giving 2 ATP (P : O = 1.5)

For FADH ₂= 6 H ⁺/O(2e - )

ATP/2e - = (6 H +/ 4 H +) = 1.5

7 0
3 years ago
How do Nitrate levels vary between tap water bottled water distilled water and outdoor water?
Ganezh [65]
  • The key difference between tap water and distilled water is that tap water may contain impurities whereas distilled water does not contain impurities. Water covers more than 70% of the earth' surface. Thus, there is less than 1% of water left for direct human use.

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8 0
2 years ago
An archaeologist finds 14C in a sample of material to be decaying at 20 Geiger Counter clicks per second. A modern equivalent sa
Kay [80]

Answer:

17188 years

Explanation:

Recall the formula;

0.693/t1/2 = 2.303/t log(No/N)

t1/2 = half life of 14C

No = initial activity of 14C

N = activity of 14C at time t

t = age of the sample

Substituting values

0.693/5730= 2.303/t log(160/ 20)

1.21 * 10^-4= 2.0798/t

t = 2.0798/1.21 * 10^-4

t = 17188 years

4 0
3 years ago
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