The distance traveled by first car is 50t + 100.
The distance traveled by second car is 70t.
The distance between the two cars after time, t is d = 100 - 20t.
The ratio of the distance traveled by the cars is (70t) / (50t + 100).
<h3>
Distance traveled by each vehicle is calculated as follows;</h3>
The distance traveled by each vehicle at the given time is calculated as follows;
<h3>Distance traveled by first car</h3>
D₁ = speed x time
D₁ = 50(t + 2)
D₁ = 50t + 100
<h3>Distance traveled by the second car</h3>
D₂ = 70t
<h3>Distance between the two cars after time, t</h3>
d = D₁ - D₂
d = (50t + 100) - 70t
d = 100 - 20t
<h3>Ratio of the distance traveled by the cars</h3>
D₂/D₁ = (70t) / (50t + 100)
Learn more about distance traveled by a vehicle here: brainly.com/question/6504879
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Try this solution, note, the suggested option is not the shortest way.
Answer:
3400 feet
Step-by-step explanation:
Distance between building 1 and building 2 = |5+3| = 8
Distance between building 2 and building 3 = |4+5| = 9
Distance between building 3 and building 4 = |-3-5| = 8
Distance between building 4 and building 1 = |4+5| = 9
total distance = 8 x 2 + 9 x 2 = 34
total distance in feet = 34 x 100 = 3400 feet
Answer:
5%
Step-by-step explanation:
Lets say 10 add a 0 = 100 9.5 add a 0 = 95.0 (move ok decimal place) so there is a 5% error.
