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Elina [12.6K]
3 years ago
7

)

Chemistry
1 answer:
xenn [34]3 years ago
3 0

Answer:

Its C hope it helped

Explanation:

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Answer:

CHO2- ion

Explanation:

We have the lewis structure of a formate-ion here

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luda_lava [24]

Answer:

See explanation

Explanation:

In this case, we have to check two variables:

1) The leaving group

2) The carbon bonded to the leaving group.

Let's check one by one:

<u>2-chloro-3-methylbutane</u>

<u />

In this molecule, the leaving group is "Cl", the carbon bonded to the leaving group has two neighbors. Therefore, we have a <u>secondary substrate.</u>

<u>1-phenylpropan-1-ol</u>

<u />

In this molecule, the leaving group is "OH", the carbon bonded to the hydroxyl group has two neighbors also. So, we have a <u>secondary substrate.</u>

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<u />

In this case, the leaving group is "OTs" (Tosylate), the carbon bonded to the tosylate group has as a neighbor a double bond. Therefore, we have an <u>allylic substrate.</u>

<u>3a-bromooctahydro-1H-indene</u>

<u />

In this molecule, the leaving group is "Br", the carbon bonded to the bromine has three neighbors. So, we have a <u>tertiary substrate.</u>

<u>1-iodo-3-methylbutane</u>

<u />

In this molecule, the leaving group is "I", the carbon bonded to the iodide has only one neighbor. So, we have a <u>primary substrate.</u>

<u />

See figure 1

I hope it helps!

<u />

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The answer to your question is D.
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