Answer:
pH of the buffer is 7.33
Explanation:
The mixture of the ions H₂PO₄⁻ and HPO₄²⁻ produce a buffer (The mixture of a weak acid, H₂PO₄⁻, with its conjugate base, HPO₄²⁻).
To find pH of a buffer we use H-H equation:
pH = pka + log [A⁻] / [HA]
<em>Where A⁻ is conjugate base and HA weak acid.</em>
<em />
For the H₂PO₄⁻ and HPO₄²⁻ buffer:
pH = pka + log [HPO₄²⁻] / [H₂PO₄⁻]
Computing values of the problem:
pH =7.21 + log [0.125M] / [0.095M]
pH = 7.33
<h3>pH of the buffer is 7.33</h3>
<em />
Explanation:
Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:
Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.
Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.
However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.
Elimination of the hydrogen from the methyl group is easier.
Thus, the major product will A
Answer:
The reaction will shift to the right
Explanation:
In the reaction:
NO(g) + NO₂(g) ⇌ N₂O₃(g)
Kp of reaction is:
= 0.03
<em>Where P represents the pressures in equilibrium</em>
Replacing in the kP formula the initial pressures:
= 0.001
As the <em>Reaction quotient (Q) </em>is less than kP, <em>the reaction will shift to the right </em>producing more N₂O₃ until Q = kP.
Answer:
Co
H20 somewhat ionic as well as covalent
SO2 is covalent
K2O is ionic
O2 ionic with somewhat covalent bonds
Answer:
4O₂ (g) + 1/2C₅H₁₂ (g) → 5/2CO₂ (g) + 3H₂O (g)
4 would be the smallest possible integer for O₂
Explanation:
The balanced equation is this one:
8O₂ (g) + C₅H₁₂ (g) → 5CO₂ (g) + 6H₂O (g)
If we divide stoichiometry /2 (the half) we can consider that we use, the smallest possible integers.
8/2O₂ (g) + 1/2C₅H₁₂ (g) → 5/2CO₂ (g) + 6/2H₂O (g)
4O₂ (g) + 1/2C₅H₁₂ (g) → 5/2CO₂ (g) + 3H₂O (g)