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3 years ago

WILL MARK BRAINLY

Chemistry

2 answers:

murzikaleks [220]3 years ago

4 0

Answer:

So copper is a lattice of positive copper ions with free electrons moving between them. ... The electrons can move freely through the metal. For this reason, they are known as free electrons. They are also known as conduction electrons, because they help copper to be a good conductor of heat and electricity.

s2011353 avatar

Why does copper have such a high electrical conductivity?

Thus, copper is a lattice of positive copper ions with the movement of free electrons among them. Due to movement of electrons freely through the metal, they are also known as conduction electrons. The presence of these conduction electrons makes the copper a good conductor of electricity and heat.

Explanation:

blondinia [14]3 years ago

4 0

Answer: lattice of positive copper ions with free electrons moving between them

Explanation:

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If we take 2.2 grams of CO2, 6.02 X 1021 atoms of nitrogen and 0.03 gram atoms of sulphur , then the molar ratio of C, N, and O

Zanzabum

Answer: -

5 : 1 : 3

Explanation: -

Mass of CO₂ = 2.2 g

Molar mass of CO₂ = 44 g / mol

Number of moles of CO₂ = $\frac{Mass}{Molar mass}$

= $\frac{2.2}{44}$

= 0.05 mol

Number of atoms of nitrogen = 6.02 x 10²¹

Number of moles of nitrogen = $\frac{Number of atoms of nitrogen}{Avogadro's number}$

= $\frac{6.02x1021}{6.02x1023}$

= 0.01 mol

0.03 gram atom of sulphur means 0.03 moles of sulphur.

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7 0

4 years ago

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Svet_ta [14]

B & C

Explanation:

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4 years ago

At 500°C the equilibrium constant, Kp, is 4.00 × 10–4 for the equilibrium: 2HCN(g) H2(g) + C2N2(g) What is Kp for the following

Andrews [41]

Answer: The value of $K_p$ for the equation is $2.5\times 10^3$

Explanation:

The given chemical reaction is:

$2HCN(g)\rightleftharpoons H_2(g)+C_2N_2(g);K_1$

The chemical equation for which the equilibrium constant is to be calculated follows:

$H_2(g)+C_2N_2(g)\rightleftharpoons 2HCN(g);K_p$

As, the equation is the result of the reverse of given reaction. So, the equilibrium constant for the equation will be the inverse of equilibrium constant for the given reaction.

The value of equilibrium constant for the equation is:

$K_p=\frac{1}{K_1}$

We are given:

$K_1=4.00\times 10^{-4}$

Putting values in above equation, we get:

$K_p=\frac{1}{4.00\times 10^{-4}}=2.5\times 10^3$

Hence, the value of $K_p$ for the equation is $2.5\times 10^3$

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4 years ago

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Advocard [28]

Answer:

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kodGreya [7K]

Answer:

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