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3 years ago

Which units are used to measure force? newtons feet miles grams

Chemistry

2 answers:

Paraphin [41]3 years ago

6 0

I'm pretty sure it's Newton's

miv72 [106K]3 years ago

3 0

A. i just took the quiz <span />

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Which of the following is something a school might dictate? *

Mazyrski [523]

Answer:

MOST likely b

Explanation:

4 0

2 years ago

What is the sum of the coefficients in the balanced chemical equation for the combustion of acetone, c3h6o(l), in air?

WITCHER [35]

The sum of the coefficients in the balanced chemical equation for combustion of acetone C3H6O in air is 11

explanation

<h2>write a balanced chemical equation for reaction</h2>

that is; C3H6O + 4O2 → 3CO2 +3H2O

coefficient is the number in front of the chemical formula

the sum of coefficient is therefore= 1 ( in front of C3H6O) + 4 ( in front of O2) + 3 ( in front of CO2) + 3 ( in front of H2O) = 11

6 0

2 years ago

Sience question ....

GrogVix [38]

Answer:

extended structure

Explanation:

7 0

2 years ago

Read 2 more answers

Consider the reaction to produce methanolCO(g) + 2H2 (g) <-----> CH3OHAn equilibrium mixture in a 2.00-L vessel is found t

MariettaO [177]

Answer : The value of $K_c$ of the reaction is 10.5 and the reaction is product favored.

Explanation : Given,

Moles of $CH_3OH$ at equilibrium = 0.0406 mole

Moles of $CO$ at equilibrium = 0.170 mole

Moles of $H_2$ at equilibrium = 0.302 mole

Volume of solution = 2.00 L

First we have to calculate the concentration of $CH_3OH,CO\text{ and }H_2$ at equilibrium.

$\text{Concentration of }CH_3OH=\frac{\text{Moles of }CH_3OH}{\text{Volume of solution}}=\frac{0.0406mole}{2.00L}=0.0203M$

$\text{Concentration of }CO=\frac{\text{Moles of }CO}{\text{Volume of solution}}=\frac{0.170mole}{2.00L}=0.085M$

$\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.302mole}{2.00L}=0.151M$

Now we have to calculate the value of equilibrium constant.

The balanced equilibrium reaction is,

$CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)$

The expression of equilibrium constant $K_c$ for the reaction will be:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.0203)}{(0.085)\times (0.151)^2}$

$K_c=10.5$

Therefore, the value of $K_c$ of the reaction is, 10.5

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.

When $K_{c}$ ; the reaction is reactant favored.

When $K_{c}=1$ ; the reaction is in equilibrium.

As the value of $K_{c}>1$ . So, the reaction is product favored.

7 0

3 years ago

How many grams are in 4.0 moles of lithium

Fittoniya [83]

Answer:

The correct answer is 27.764 grams.

Explanation:

A standard scientific unit for determining the large quantities of very small entities like molecules, atoms, or other specific particles is termed as a mole. The molecular weight of lithium is 6.941 grams per mole. Thus, one mole of lithium has 6.941 grams.

If, 1 mole of Li has 6.941 grams, then 4 moles of Lithium will have,

= Molecular mass of lithium/1 mole * 4 mole

= 6.941 gram per mole/1 mole * 4 moles.

= 27.764 grams

3 0

2 years ago