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3 years ago

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Chemistry

1 answer:

pishuonlain [190]3 years ago

5 0

Answer:

5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2

Explanation:

shooo i needta be a jonir in high school n im only a freshman

lemme quit dha kapp i be using go.ogle for sum of dese buh ik these elements from the pheriotic table n ik that u gotta make both sides even

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The reaction betwen aluminum and iron (III) oxide can

Alona [7]

Answer : The mass of $Al_2O_3$ formed will be, 468.18 grams.

Solution : Given,

Mass of Al = 124 g

Mass of $Fe_2O_3$ = 601 g

Molar mass of Al = 27 g/mole

Molar mass of $Fe_2O_3$ = 160 g/mole

Molar mass of $Al_2O_3$ = 102 g/mole

First we have to calculate the moles of Al and $O_2$ .

$\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{124g}{27g/mole}=4.59moles$

$\text{ Moles of }Fe_2O_3=\frac{\text{ Mass of }Fe_2O_3}{\text{ Molar mass of }Fe_2O_3}=\frac{601g}{160g/mole}=3.76moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe$

From the balanced reaction we conclude that

As, 2 mole of $Al$ react with 1 mole of $Fe_2O_3$

So, 4.59 moles of $O_2$ react with $\frac{4.59}{2}=2.295$ moles of $Fe_2O_3$

From this we conclude that, $Fe_2O_3$ is an excess reagent because the given moles are greater than the required moles and $Al$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Al_2O_3$

From the reaction, we conclude that

As, 2 mole of $Al$ react to give 2 mole of $Al_2O_3$

So, 4.59 moles of $O_2$ react to give $\frac{2}{2}\times 4.59=4.59$ moles of $Al_2O_3$

Now we have to calculate the mass of $Al_2O_3$

$\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3$

$\text{ Mass of }Al_2O_3=(4.59moles)\times (102g/mole)=468.18g$

Therefore, the mass of $Al_2O_3$ formed will be, 468.18 grams.

3 0

3 years ago

If a 0.50 M solution of K2SO4 is slowly poured into a beaker containing 0.25 Mbarium nitrate and 0.30 M lead (II) nitrate at 25o

postnew [5]

Answer: The first precipitate formed is Barium Sulphate

Explanation:

This is because the reaction that takes place will be as follows:

K2SO4 + Ba (NO3)2 ------> BaSO4 + K2(NO3)2

And K2SO4 + Pb(NO3)2 -----> PbSO4 + K2(NO3)2

Considering the concentration of Barium Nitrate which is lower than that of Lead Nitrate it tends to attain equilibrium faster and the Barium salt or precipitate is formed....

6 0

3 years ago

A chemist has dissolved a certain substance in water. The chemist knows that more of the substance could be dissolved into the w

iren2701 [21]

Answer:

Therefore it has not become a saturated solution

3 0

3 years ago

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Balance the following equations. Do not include the states of matter.<br><br> (a) C + O2 → CO

krek1111 [17]

Answer: