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3 years ago

Type the correct answer in each box.

Chemistry

1 answer:

pishuonlain [190]3 years ago

5 0

Answer:

5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2

Explanation:

shooo i needta be a jonir in high school n im only a freshman

lemme quit dha kapp i be using go.ogle for sum of dese buh ik these elements from the pheriotic table n ik that u gotta make both sides even

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How does thermal energy result from friction

dlinn [17]

Thermal energy from friction. ... All the work done by the friction force results in a transfer of energy into thermal energy of the box-floor system. This thermal energy flows as heat within the box and floor, ultimately raising the temperature of both of these objects. Figure 1: Man pushing a box opposed by friction.

4 0

3 years ago

Water 2270g is heated until it just begins to boil. If the water absorbs 5.51 ×10^5 J of heat in the process, what was the initi

kolbaska11 [484]

Answer:

42.01 °C

Explanation:

<u>Step 1: explain the problem</u>

We have to find the initial temperature, when a certain amount of heat raises this sample of water to its boiling point ( 100 °C)

⇒this amount of heat = 5.51 x 10Δ^5 J

We will use the formule : Q = mcΔ T

with Q = heat transfer ( J)

with m = mass of the substance (g)

with c = specific heat ( J/g °C)

with Δ T = temperature change ( in °C or K)

Water has a specific heat of 4.186 J/g °C

<u>Step 2 : Calculate the initial temperature </u>

We have to rearrange the formule first:

Δ T = Q / mc

In this case we have :

Δ T = 5.51 * 10^5 J / 2270 g * 4.186 J/g °C = 57.99

⇒ The final temperature of the water is the boiling point (100 °C) and the change of temperature is 57.99. This means that the boiling point is 57.99 °C higher than the initial temperature.

This means : Δ T = Tboiling point - Tinitial

Δ T = 57.99 °C = 100 °C - Tinitial

Tinitial = 100 °C - 57.99 °C = 42.01 °C

The initial temperature of the water is 42.01 °C

6 0

4 years ago

4.14 Oxygen requirement for growth on glycerol Klebsiella aerogenes is produced from glycerol in aerobic culture with ammonia as

Iteru [2.4K]

Answer:

0.37 g

Explanation:

The molecular weight for Glycerol = 92

Number of Carbon atoms in glycerol (x) $C_3H_8O_3$ = 3

Molecular weight of the Biomass ( Klebsiella aerogenes )

= $CH_{1.73}O_{0.43}N_{0.24}$

= $\frac{23.97}{0.92}$

= 26.1

From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as $\delta _g$ ) as follows:

= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)

= 4.15

Given that the yield of the Biomass = 0.40 g

However;

C = $Yield of Biomass *\frac{Molecular weight of substrate}{Molecular weight of the Biomass}$

C = $0.40*\frac{92}{26.1}$

C = 1.41 g

Now , the oxygen requirement can be calculated as:

= $\frac{1}{4}*(n*S - C * \delta _{g})$

= $\frac{1}{4}(3*4.7-1.41*4.15)$

= 2.1 g/mol

Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.

Now converting it to mass terms; we have:

= $2.1*\frac{number of mole of oxygen}{molecular weight of glycerol}$

= $2.1 * \frac{16}{92}$

= 0.3652 g

≅ 0.37 g

∴ The oxygen requirement for this culture in mass terms = 0.37 g

3 0

3 years ago

What mass of benzene is cooled from 83.8 °C to 77.1 °C when 167 J of energy is transferred out of the system? (The specific heat

dexar [7]

Answer:

14.32g

Explanation:

Initial temperature = 83.8°C

Final temperature = 77.1°C

Temperature change, ΔT = 83.8°C - 77.1°C = 6.7

Heat, H = 167J

Specific heat, c = 1.740J/g °C

m = ?

All these parameters are related with the equation below;

H = mcΔT

m = H / cΔT

m = 167 / (1.740 * 6.7)

m = 167 / 11.658 = 14.32g

3 0

3 years ago

Roman mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. Find the number of lit

inysia [295]

Let the 8% solution be A, the 20% solution be B and the final solution be C.

C = A + B
C = 12 + B

0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters

C = 12 + 24
C = 36 Liters

3 0

4 years ago