Answer:
4 ± 1/2sqrt(x) = y
This is not a function
Step-by-step explanation:
f(x) = (8-2x)^2
y = (8-2x)^2
To find the inverse function, exchange x and y and then solve for y
x = (8-2y)^2
Take the square root of each side
±sqrt(x) = 8-2y
Subtract 8 from each side
-8±sqrt(x) = 8-8-2y
-8±sqrt(x) = -2y
Divide by -2
-8/-2± 1/2sqrt(x) = -2/-2y
4 ± 1/2sqrt(x) = y
This is not a function
Just do 23 minus 6 and that should be the answer because the y-ccordinate is in the same place
Answer:
110
Step-by-step explanation:
that's what I got, I apologize if it's incorrect
In algebraic terms this is:
![10-(x+3)=5\\10-x-3=5\\10-x=5+3\\10-x=8\\-x=8-10\\-x=-2\\x=2](https://tex.z-dn.net/?f=10-%28x%2B3%29%3D5%5C%5C10-x-3%3D5%5C%5C10-x%3D5%2B3%5C%5C10-x%3D8%5C%5C-x%3D8-10%5C%5C-x%3D-2%5C%5Cx%3D2)
The integer is 2.