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jarptica [38.1K]
3 years ago
13

Is light a wave or a particle? (points 1)

Physics
1 answer:
FinnZ [79.3K]3 years ago
4 0
None of the choices is an acceptable answer. Light ... as well as all other forms of electromagnetic radiation ... is both. When you run light through an experiment built to detect particles ... such as photoelectric stimulation of electron emission ... the light behaves like a stream of particles. When you set up an experiment built to measure and detect waves ... like reflection, refraction, diffraction, dispersion, constructive and destructive interference ... the light does all of those things too. Scientists would only debate the question if light absolutely positively had to be one or the other, and could not possibly be both. Such a debate isn't necessary, and scientists no longer waste their time arguing about it. Light is both. Between Maxwell and Einstein, the wave/particle duality of light had been convincingly demonstrated well over a hundred years ago.
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The flagpole is held vertical by two ropes. The first of these ropes has a tension in it of 100 N and is at an angle of 60° to t
KatRina [158]

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T₂ = 123.9 N,  θ = 66.2º

Explanation:

To solve this exercise we use the law of equilibrium, since the diaphragm does not appear, let's use the adjoint to see the forces in the system.

The tension T1 = 100 N, we create a reference frame centered on the pole

X axis

       T₁ₓ - T_{2x} = 0

        T_{2x}= T₁ₓ

Y axis y

      T_{1y} + T_{2y} - 200N = 0

      T_{2y} = 200 -T_{1y}

let's use trigonometry to find the component of the stresses

         sin 60 = T_{1y} / T₁

         cos 60 = t₁ₓ / T₁

         T_{1y} = T₁ sin 60

         T1x = T₁ cos 60

         T_{1y}y = 100 sin 60 = 86.6 N

         T₁ₓ = 100 cos 60 = 50 N

for voltage 2 it is done in the same way

         T_{2y} = T₂ sin θ

         T₂ₓ = T₂ cos θ

we substitute

         

           T₂ sin θ= 200 - 86.6 = 113.4

           T₂ cos θ = 50              (1)

to solve the system we divide the two equations

           tan θ = 113.4 / 50

           θ = tan⁻¹ 2,268

           θ = 66.2º

we caption in equation 1

           T₂ cos 66.2 = 50

           T₂ = 50 / cos 66.2

           T₂ = 123.9 N

8 0
3 years ago
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