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2 years ago

5. Name one career in the health and fitness field that interests you.

Physics

1 answer:

BartSMP [9]2 years ago

3 0

Answer:

I've always wanted to be a nurse. growing up my auntie used to show me a lot of stuff about becoming a nurse since she us one.

You might be interested in

A physicist found that a force of 0.72N was measured between two charged sphere. The distance between the sphere was 0.90 m. Cal

aalyn [17]

What you can use is coulomb's inverse square law that states that force varies inversly as the square of distance. <span>It menas that the force is calculated by dividing by distance squared. what this does is essentially as the distance doubles, the forces is reduced by a factor of 4 or can be divided by 4. Force at 0.5m=2.3328N. And brings you ti the answer</span>

7 0

3 years ago

Read 2 more answers

. A force of 3.0 N acts through a distance of 12 m in

musickatia [10]

Answer:

<h3>The answer is 36 J</h3>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 3 × 12

We have the final answer as

Hope this helps you

6 0

2 years ago

Test your prediction through calculation for the situations of the clay bob and the bouncy ball. Assume each has a mass of 100 g

melamori03 [73]

Answer:

a) Δp = -2.0 kgm / s, b) Δp = -4 kg m / s

Explanation:

In this exercise the change in moment of a ball is asked in two different cases

a) clay ball, in this case the ball sticks to the door and we have an inelastic collision where the final velocity of the ball is zero

Δp = p_f - p₀

Δp = 0 - m v₀

Δp = - 0.100 20

Δp = -2.0 kgm / s

b) in this case we have a bouncing ball, this is an elastic collision, as the gate is fixed it can be considered an object of infinite mass, therefore the final speed of the ball has the same modulus of the initial velocity, but address would count

v_f = - v₀

Δp = p_f -p₀

Δp = m v_f - m v₀

Δp = m (v_f -v₀)

Δp = 0.100 (-20 - 20)

Δp = -4 kg m / s

6 0

3 years ago

An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10

Nadya [2.5K]

Answer:

1822.14 J/kg C

Explanation:

Mass of aluminum = 0.100 kg

Mass of Water = 0.250 kg

Mass of copper = 0.300 kg

Mass of unknown object = 0.70 kg

Initial temperature of Aluminum = 10 C

Initial temperature of water = 10 C

Initial temperature of copper = 30 C

Initial temperature of = 100 C

Final temperature of all substances = 20 C

Change in temperature of each of them Aluminum, water , copper and unknown material respectively = 10 C , 10 C , -10 C, -80 C respectively

Specific heat of each of them Aluminum, water , copper and unknown material respectively = 900,4186,387 and c respectively.

Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j

heat lost by copper and unknown material =(0.3)(387)(-10) = -1161

heat lost by unknown material = (0.070)(c)(-80) = -5.6 c

Now solve for c using the calorimetry principle.

Heat lost + Heat gained = 0

⇒ -5.6 c = -11365 - (-1161) = -10204 j

Specific heat of unknown material = - 10204 / -5.6

= 1822.14 j/kg C

b) Material having a specific heat of 1800 j /kg C is

Polyurethane elastomer.

4 0

3 years ago

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the high

m_a_m_a [10]

Answer:

factor that bug maximum KE change is 0.52284

Explanation:

given data

vertical distance = 6.5 cm

ripples decrease to = 4.7 cm

solution

We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

KE = (0.5) × m × A² × ω² .................1

and kinetic energy is directly proportional to square of the amplitude.

$\frac{KE2}{KE1} = \frac{A2^2}{A1^2}$ .............2

$\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}$

$\frac{KE2}{KE1}$ = 0.52284

so factor that bug maximum KE change is 0.52284

5 0

3 years ago