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dalvyx [7]
3 years ago
15

Squid use jet propulsion for rapid escapes. A squid pulls water into its body and then rapidly ejects the water backward to prop

el itself forward. A 1.5 kg squid (not including water mass) can accelerate at 20 m/s2 by ejecting 0.15 kg of water.?

Physics
1 answer:
Setler [38]3 years ago
5 0

Answer:

a. FTh = 30 N

b. Fw = 30 N

c. a = 200 m/s2

Explanation:

See full explanation in the picture. Please rate as brainliest

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Two ropes support a load of 539 kg. The two ropes are perpendicular to each other, and the tension in the first rope is 1.88 tim
7nadin3 [17]

Answer:

T₂ = 2482.34 N

Explanation:

Equations of balance of forces

Look at the force diagram in the attached graph:

∑Fx=0

T₂cos α  -T₁senα   = 0 Equation (1)

∑Fy=0

T₁cos α +T₂sinα-W =0 Equation(2)

Data

m=539 kg

g=  9.8 m/s²

W= m*g= 539 kg* 9.8 m/s²= 5282.2 N

T₁ = 1.88T₂

Problem development

in the equation (1)

T₂cos α-(1.88T₂)senα   = 0 We divided the equation by ( T₂cos α)

1 - (1.88)tanα   = 0

tanα= 1/(1.88)

tanα= 0.5319

\alpha =tan^{-1} (0.5319)

α = 28°

T₂=(1.88T₂)tanα

in the equation (2)

(1.88T₂)cos α+ T₂sinα - 5282.2 =0 We divided  the equation by cos α

1.88T₂+ T₂tanα - 5282.2/cos α =0

1.88T₂+ T₂tan(28°) - 5282.2/(cos 28°) =0

1.88T₂+ (0.53)T₂- 5982.46 =0

(2.41)T₂ = 5982.46

T₂ = 5982.46/(2.41)

T₂ = 2482.34 N

4 0
3 years ago
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