Answer:

Step-by-step explanation:
We are given that Chantal drives at a constant speed of 55 miles per hour.
If, d represents the total distance in miles, and
h represents number of hours, the following equation can be used to express the given situation:

For every hour, a distance of 55 miles is covered.
Thus, if h = 1, 
If h = 2,
.
Therefore,
, is an ideal equation that represents the situation given in the question above.
Power and chain rule (where the power rule kicks in because
):

Simplify the leading term as

Quotient rule:

Chain rule:


Put everything together and simplify:







For chemistry you would need to get an 84.
For Spanish you would need to get an 82.
Best of luck
Answer:
93 fluid ounce
Step-by-step explanation:
Answer:
A) w=3
Step-by-step explanation:
4 x 3 = 12
This is the work when you plug in the numbers in the varible w