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Stolb23 [73]
3 years ago
14

17. Which of the following is NOT a testable

Physics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

c. testing student opinions

Explanation:

opinions aren't factual and they would not aide an experiment if it wasn't for a social experiment.

You might be interested in
Select the correct answer.
kvasek [131]

Answer:

8.37×10⁻⁴ N/C

Explanation:

Electric Field: This is the ratio of electrostatic force to electric charge. The S.I unit of electric field is N/C.

From the question, the expression for electric field is given as,

E = F/Q.......................... Equation 1

Where E = Electric Field, F = force experienced by the charged balloon, Q = Charge on the balloon.

Given: F = 8.2×10⁻² Newton, Q = 9.8×10 Coulombs = 98 Coulombs

Substitute these values into equation 1

E = 8.2×10⁻² /98

E = 8.37×10⁻⁴ N/C

Hence the Electric Field of the charged balloon =  8.37×10⁻⁴ N/C

4 0
3 years ago
Read 2 more answers
NASA launches a probe with a mass of 15,000 kg to another planet more massive than Earth. Which statement is true about the prob
vivado [14]

Answer: The weight of the probe will increase.

8 0
3 years ago
What do you mean by specific heat capacity?​
Dennis_Churaev [7]

Please mark me as Brainliest ......

6 0
3 years ago
Many arlines restrict maximum mass of a case to 23 kg why​
Alexxandr [17]

Answer:

weight

Explanation:

the weight of an object on an airline is one of the most important thing a pilot has to consider when prepping a flight and that is because if there is too much weight then the plane simply can't fly. imagine if everyone wanted to bring a 50 kg box. there are at least  200 people.  that alone is 10,000 lg of weight than you have to factor in all the people, wires on the plane, and certain appliances that some planes have.

7 0
3 years ago
Will mark as BRAINLIEST.......
irinina [24]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

x=4t^3+3t^2-5t+2

Where,

x is in meters and t is in sec

We know that,

Velocity,

v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5

(a) i. t = 2 s

v=12(2)^2+6(2)-5=55\ m/s

At t = 4 s

v=12(4)^2+6(4)-5=211\ m/s

(b) Acceleration,

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6

Pu t = 3 s in above equation

So,

a=24(3)+6\\\\a=78\ m/s^2

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²

6 0
3 years ago
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