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ohaa [14]
3 years ago
14

• Describe the main ideas of physical science

Physics
1 answer:
arlik [135]3 years ago
5 0
Branch of science that studies matter and its motion through space and time, along with related concepts such as energy and force. Describing the nature, measuring and quantifying of bodies and their motion, and dynamics.
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On which planet can you jump about the same height as Earth? Explain your answer.
Debora [2.8K]

Answer:

Venus and Earth

Explanation:

The force of gravity depends on your mass AND the mass of the planet you stand on. Earth and Venus are about the same size, so they have about the same mass. If you go to Venus, your mass hasn't changed, and the planet mass is almost the same as earth- so the force of gravity on you (AKA your weight) will be the same.

8 0
3 years ago
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The ???? ,of an object is a vector that is directed toward<br> the center of the Earth.
Aleks04 [339]

<u>The Weight  </u>is a vector whose magnitude is the product of the mass m of the object and the magnitude of the local gravitational acceleration. Its always directed toward  the center of the Earth.

5 0
3 years ago
In order to convert sunlight energy into usable energy the cell needs
Anestetic [448]

Cells do not use the energy from oxidation reactions as soon as it is released. Instead, they convert it into small, energy-rich molecules such as ATP and nicotinamide adenine dinucleotide (NADH), which can be used throughout the cell to power metabolism and construct new cellular components.

6 0
3 years ago
A jogger runs 10.0 blocks do east, 5.0 blocks due South, and another two. Zero blocks do east. Assume all blocks are equal size,
Annette [7]

Jogger moves in three displacements

d1 = 10 blocks East

d2 = 5 blocks South

d3 = 2 blocks East

now we can say

total displacement towards East direction will be

d_x = 10 + 2= 12 blocks

Total displacement towards South

d_y = 5 block

now to find the net displacement we can use vector addition

d = \sqrt{d_x^2 + d_y^2}

d = \sqrt{12^2 + 5^2}

d = 13 blocks

<em>so magnitude of net displacement will be equal to 13 blocks</em>

6 0
3 years ago
A thin rod of length 0.83 m and mass 110 g is suspended freely from one end. It is pulled to one side and then allowed to swing
VARVARA [1.3K]

Explanation:

(a)  The given data is as follows.

    Length of the rod, L = 0.83 m

    Mass of the rod, m = 110 g = 0.11   (as 1 kg = 1000 g)

 At the lowest point, angular speed of the rod (\omega) = 5.71 rad/s

First, we will calculate the rotational inertia of the rod about an axis passing through its fixed end is as follows.

      I = I_{CM} + mh^{2}

        = \frac{1}{12}mL^{2} + m(\frac{L}{2})

        = \frac{1}{12} \times 0.11 \times (0.83)^{2} + 0.11 \times \frac{0.83}{2}

        = 0.00631 + 0.415

        = 0.42131 kg m^{2}

Therefore, kinetic energy of the rod at its lowest point will be calculated as follows.

             K = \frac{1}{2}I \omega^{2}

                = \frac{1}{2} \times 0.42131 kg m^{2} \times (5.71)^{2}

                = 6.86 J

Hence, kinetic energy of the rod at its lowest point is 6.86 J.

(b)   According to the conservation of total mechanical energy of the rod, we have

         K_{i} + U_{i} = K_{f} + U_{f}

           K_{i} = U_{f} - U_{i}

or,      mgh = K = 6.86 J

Therefore,      h = \frac{6.86}{mg}

                          = \frac{0.63}{0.11 \times 9.8}

                          = 0.584 m

Hence, the center of mass rises 0.584 m far above that position.

6 0
3 years ago
Read 2 more answers
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