From the order you gave me in the question the answer is equation number
4 1 3 2 6 5
Those are the equation numbers in ascending order based on their radius lengths
Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
Answer:
v > 4 is simplified expression.
Step-by-step explanation:
Given that:
v + 5 > 9
This expression says that when 5 is added to a variable v it will be greater than 9 So we will simplify it to get the value for variable v:
Subtracting 5 from both sides:
v + 5 - 5 > 9 - 5
v > 4
This is the simplified expression for given question.
i hope it will help you!
Answer:
The answer for f(2) is 11.
Step-by-step explanation:
f(x) = 3x2 + 2x - 5
f(2) = 3(2)2 + 2(2) - 5
f(2) = 6(2) + 4 - 5
f(2) = 12 + 4 - 5
f(2) = 16 - 5
f(2) = 11