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Misha Larkins [42]
4 years ago
6

Which name is given to the type of friction that an objects falling through the air experience

Physics
1 answer:
andrey2020 [161]4 years ago
3 0
It is called Air resistance
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The upper arm muscle is _______________ to the skin.
Nikolay [14]

Answer:

The pectoralis major, latissimus dorsi, deltoid, and rotator cuff muscles connect to the humerus and move the arm. The muscles that move the forearm are located along the humerus, which include the triceps brachii, biceps brachii, brachialis, and brachioradialis.

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Mirrors produce images by doing which of the following to light?
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Answer: C

Reflection

Explanation: Light travels in a straight line. Reflection is one of the properties of light. And this is the property in which mirror make use of. The ability of light to bounce back. It's this bouncing back characteristics of light ray that eventually produce the image of an object by the mirror.

If the light ray is absorbed, no image will be produced.

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3 years ago
If you have a calendar that shows only the phases of the moon,can you predict when spring tides and neap tides will happen ?
otez555 [7]
Moon orbits earth. it's viewable somewhere in the world every 28 days. if the place where it's viewed were by the sea, then the tidal patterns of water - high tide and low tide - could be correlated to the moon being seen or otherwise. If the moon is is visible, it presumably gives one gravitational pull on the water. If the moon is not visible, then it presumably gives a less gravitational pull. Maybe "spring" suggests a high high tide (as in growth ?) and "neap" suggests a low high tide ???
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3 years ago
Which is the product of cellular respiration? A. ATTP B. light C. oxygen D.sugar
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7 0
3 years ago
A 0.026 kg bullet is fired straight up at a falling wooden block that has a mass of 5.0 kg. The bullet has a speed of 750 m/s wh
Law Incorporation [45]

Answer:

0.198 s

Explanation:

Consider the motion of the block  before collision

v_{o} = initial velocity of block as it is dropped = 0 m/s

a = acceleration = - g

t = time of travel

v_{f} = final velocity of block before collision

Using the kinematics equation

v_{f} = v_{o} + at \\v_{f} = 0 + (-g)t\\v_{f} = - gt

m = mass of the bullet = 0.026 kg

v_{b} = velocity of block just before collision = 750 m/s

M = mass of the block = 5 kg

V = final velocity of bullet block after collision = gt

Using conservation of momentum

m v_{b} + Mv_{f} = (m + M) V\\(0.026) (750) + (5) (- gt) = (0.026 + 5) (gt)\\19.5 - 49 t = 49.2548 t\\t = 0.198 s

8 0
3 years ago
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